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Oksi-84 [34.3K]
4 years ago
10

Determine the largest integer value of x in the solution of the following inequality.

Mathematics
1 answer:
Aleonysh [2.5K]4 years ago
6 0

Answer:

x = 0

Step-by-step explanation:

Add 2x - 8 to the inequality.

... 1 ≥ 2x

Divide by 2.

... 1/2 ≥ x

The largest integer satisfying this requirement is x = 0.

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If 160 is divided by x, then the remainder is 4. What is the remainder when 315 is divided by x?
frutty [35]
Let us rewrite this equation as:
<em>160/x = some number + 4/x
</em>we can assume that some number of x's can fit into 160, but x is greater than 4 so we have a remainder.
We can figure out by using the remainder that x is completely divisible into (160-4) or 156. Knowing this we can assume that x is some factor of 156 that is greater than 4. 
Let us list the factors of 156
1,2,3,4,6,12,13,26,39,52,78,156
Now let us refer back to the restrictions we put on x.
<em>x must be > 4 as anything less than 4 would divide at least 1 more time into it. So now we are left with a bunch of other factors. And the cool thing is that all of the factors excluding anything that is = or < 4 all work for getting a remainder of 4. Thus we can use the largest factor and set it equal to x.
</em>So x = 156
then if we divide 315 by x or <em>315/x = 315/156 = 2 and a remainder of 3
so the answer would be 3.</em>
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You could try searching it up I’m sure it will pop up !
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Dmitry_Shevchenko [17]
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Read 2 more answers
8 grade math dont really uderstand it so please explain also
pishuonlain [190]

Answer: Girls weekly: 25; Girls never:40; boys yearly: 25; boys never: 20; boys total:80 monthly total: 30

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