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2 years ago

Help please. Im stuck

Mathematics

1 answer:

LUCKY_DIMON [66]2 years ago

3 0

Answer:

16 units squared

Step-by-step explanation:

First, calculate the distance between (0, 0) and (0, 4). The distance is in y, so there are 4 units in-between.

Next, calculate the distance between (0, 0) and (4, 0). This time, the distance is in x, but it is still four.

We know the dimensions of the shape are 4x4 so we just multiply.

4*4=16

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Does anyone know this one?

seropon [69]

Answer:

Multiply both sides by 2

Subtract l from both sides

Divide each side by 3

(2R -l)/3 =w

Step-by-step explanation:

R = (l+3w)/2

Multiply both sides by 2

2R = 2* (l+3w)

2R = l+3w

Subtract l from both sides

2R - l = l-l +3w

2R -l = 3w

Divide each side by 3

(2R-l) /3 = 3w/3

(2R -l)/3 =w

6 0

3 years ago

Read 2 more answers

Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

3 0

3 years ago

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What is the equation, in standard form, of a parabola that models the values in the table?

Vitek1552 [10]

Answer:

b. 4x^2 + 3x - 6

Step-by-step explanation:

The values of f(x) for the extremes of x are more positive than the value of f(x) for the middle x, so we know the parabola opens upward. That eliminates choice D.

It is probably easiest to evaluate the other expressions to see which one matches the given f(x) values. For the purpose, it is usually easier to use the Horner form of the equation.

a. f(-2) = (3(-2) +4)(-2) -6 = -2(-2) -6 = -2 ≠ 4

b. f(-2) = (4(-2) +3)(-2) -6 = -5(-2) -6 = 4 . . . . matches the given data point

c. Because (b) matches, we know this one will not.

The appropriate choice is B.