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professor190 [17]
4 years ago
9

Evaluate the exponent (-6) EE -3

Mathematics
1 answer:
Marta_Voda [28]4 years ago
3 0

Answer:

Hence final answer is -\frac{1}{216}.

Step-by-step explanation:

Expression is not typed in proper format but as per given instruction "evaluate the exponent", I think it is:

\left(-6\right)^{-3}

So let's simplify that:

\left(-6\right)^{-3}

Apply formula x^-m=1/x^m

=\frac{1}{\left(-6\right)^{+3}}


=\frac{1}{\left(-6\right)^3}


=\frac{1}{\left(-6\right)\left(-6\right)\left(-6\right)}


=\frac{1}{-216}


=-\frac{1}{216}



Hence final answer is -\frac{1}{216}.

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The 12th term in the sequence is -26.

Given,

B (n) = -4 – 2(n – 1)

We have to find the 12th term in the sequence:

To find the nth term in an arithmetic sequence:

An arithmetic sequence's nth term is determined by the formula a = a + (n - 1)d. The common difference, or d, is the difference between any two consecutive terms in an arithmetic series; it can be calculated by deducting any pair of terms starting with a and an+1.

Here,

First term, a = -4

Common difference, d = -2

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Now, let’s find 12th term

B(n) = -4 -2(n – 1)

B(12) = -4 – 2(12 – 1)

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That is, the 12th term in the sequence is -26.

Learn more about arithmetic sequence here:

brainly.com/question/11570734

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