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3 years ago

One half plus three fourths

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

(one half) plus (three fourths) is 1.25

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Find the supplement of an angle that measures 20 degrees.

OLEGan [10]

Supplementary angles add to be 180 degrees. If one angle is 20. The supplement angle is 160.
180 - 20 = 160
160 is your answer.

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2 years ago

Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B62500%7D%20" id="TexFormula1" title=" \

sashaice [31]

Answer:

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Step-by-step explanation:

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3 years ago

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Express sin P as a fraction in simplest terms.

d1i1m1o1n [39]

Answer:

1/15

Step-by-step explanation:

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3 years ago

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Figure ABCDE is similar to figure FGHIJ. What is the length of segment FG?

Viefleur [7K]

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3 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

3 years ago