Answer:
Look at pics.
Step-by-step explanation:
Hope this helps!
9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
Greatest error is half smallest measuring unit. It's measured to 0.1 cm , half that is 0.05 cm answer D.
Answer:
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Step-by-step explanation:
Freeeee? Sorry.
Answer:
The answer to your question is diameter = 19.7 in
Step-by-step explanation:
Data
Circumference = 62 in
diameter = ?
Process
1.- Write the formula of Circumference, remember that circumference = perimeter.
Perimeter = 2πr
2.- Equal the equation to the value given
2πr = 62
-Solve it for r
r = 62/2(3.14)
-Result
r = 62/6.28
r = 9.87 in
3.- Find the diameter
diameter = 2r
diameter = 2(9.87)
diameter = 19.7 in