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3 years ago

The figures are similar. Find x. 9/15 4/x

Mathematics

1 answer:

Inessa [10]3 years ago

5 0

9/15=4/x

One solution was found :

x = 20/3 = 6.667

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

9/15-(4/x)=0

Step by step solution :

Step 1 :

Simplify —

Equation at the end of step 1 :

9 4

—— - — = 0

15 x

Step 2 :

Simplify —

Equation at the end of step 2 :

3 4

— - — = 0

5 x

Step 3 :

Calculating the Least Common Multiple :

3.1 Find the Least Common Multiple

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Jonathan bought 6 cans of paint and 2/3 of a pint of special paint additive formulated to reduce mildew. Before painting his hou

gayaneshka [121]

Answer:

1/9 pint

or 2/9 cup

Step-by-step explanation:

This question is asking us to <em>divide </em>2/3 pint among 6 cans.

2/3 ÷ 6

2/3 × 1/6

= 2/18

= 1/9 pint or 2/9 cup additive

5 0

2 years ago

Evaluate using P E M D A S 2 x 3 + 4

Juli2301 [7.4K]

Step-by-step explanation:

We would do multiplication first, because of order of operations.

2x3=6

Now we add.

6+4=10

hope it helps! :3

8 0

2 years ago

Read 2 more answers

Joan needs to estimate the size of her bedroom so that she can buy enough paint to cover the walls. Two of the walls measure 2.8

labwork [276]

The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.

The measurement of two of the walls is 2.86 metres and 3.16 metre

Area of the two walls = 2(length x breadth)

Area = 2(2.86 x 3.16) = 18.0752 m²

The measurement of the other two walls is 2.86 metres and 3.42 metres

Area of the two walls = 2(length × breadth)

Area = 2(2.86 × 3.42) = 19.5624 m²

Total area = 18.0752 + 19.5624 = 37.6376 m²

If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be

No. of cans = Total area/Area covered by one can of paint

No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)

3 0

1 year ago

Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length.

sweet [91]

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

$W=3+\frac{1}{4} L$

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

$2(L+W)=10+2L$

now, we can simplify it

$2L+2W=10+2L$

subtract both sides by 2L

$2L+2W-2L=10+2L-2L$

$2W=10$

$W=5$

now, we can find L

$5=3+\frac{1}{4} L$

subtract both sides 3

$5-3=3-3+\frac{1}{4} L$

$2=\frac{1}{4} L$

multiply both sides by 4

$4*2=4*\frac{1}{4} L$

$L=8$

so,

length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

4 0

3 years ago

The central angle of a circle measures 108 degrees and intercepts an arc of 6pi inches.

damaskus [11]

An arc is a part of the circumference of a circle and the angles that subtend the arcs are proportional to the length of the arc.

So, you basically have two arcs to compare: a 10cm arc and a 60cm arc. But the 60cm arc also happens to be the circumference in this case, so you know that the angle that subtends that arc is 360 degrees (the whole circle). The 10cm arc is 1/6 of the whole circumference so the angle is going to be 1/6 of 360 degrees, which is <span>60 degrees.</span>

8 0

3 years ago