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AVprozaik [17]
3 years ago
10

What is the range of the given function ? {(-2,0),(-4,-3),(2,-9),(0,5),(-5,7)}

Mathematics
1 answer:
seraphim [82]3 years ago
6 0

Answer:

{0,-3,-9,5,7}

Step-by-step explanation:

range = all y values

function =(x,y)

so all the second values are ranges

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An account earns simple annual interest. You deposit $600 into an account at 5% interest rate for 2 years. (a) Find the interest
Ilia_Sergeevich [38]

Answer:

(a) $60 | (b) $660

Step-by-step explanation:

We can use the simple interest formula for this:

I=Prt

<em>I = interest amount</em>

<em>P = principal amount</em>

<em>r = interest rate (decimal form)</em>

<em>t = time (years)</em>

<em />

First, change 5% into its decimal form:

5% -> \frac{5}{100} -> 0.05

Next, plug in the values into the equation:

I=600(0.05)(2)

I=60

<em>The interest earned is $60. To find the total balance, just add the $600 back.</em>

600+60=660

The total interest earned is $60 and the total is $660.

4 0
3 years ago
What is the volume of the solid figure?
romanna [79]

Answer:

The volume of the solid figure = Volume of the first cuboid + Volume of the second cuboid

The volume of the solid figure = 15×5×5 + 5×5×10

Or, The volume of the solid figure = 375 + 250

Or, The volume of the solid figure = 625 inch³

Therefore, the volume of the solid figure = 625 inch³

Step-by-step explanation:

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3 years ago
A carpet cleaning business has 100 customers when they charge $125 for a cleaning. Research shows that every $5 reduction in pri
Dennis_Churaev [7]
Since a $5 decrease in price increases customers by 20 we can say that we have two points:

(125,100) and (120,120), from these we can find the slope or rate of change of customers as a function of price...

m=20/-5

m=-4

m=-4

c(p)=-4p+b, now we can use (125,100) to solve for b

100=-4(125)+b

100=-500+b

600=b, so our number of customers as a function of price is:

c(p)=600-4p

Revenue will simply be the number of customers times the price charged per customer...or p*c(p):

r(p)=600p-4p^2

We can find price that creates maximum revenue by finding when the derivative is equal to zero...

dr/dp=600-8p

dr/dp=0 only when

0=600-8p

8p=600

p=75

So the price that maximizes revenue is $75.

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Find the value of x in each case.
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