Question

Solve for x in the following equation.

Answer 1

For this case we must solve the following equation of the second degree:

$x ^ 2 + 6x-16 = 0$

The solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = 6\\c = -16$

Substituting:$x = \frac {-6\pm \sqrt {6 ^ 2-4 (1) (- 16)}} {2 (1)}$

$x = \frac{-6\pm\sqrt{36+64}}{2}$

$x = \frac {-6 \pm \sqrt {100)}} {2}\\x = \frac {-6 \pm10} {2}$

So:

$x_ {1} = \frac {-6 + 10} {2} = \frac {4} {2} = 2\\x_ {2} = \frac {-6-10} {2} = \frac {-16} {2} = - 8$

Answer:

$x_ {1} = 2\\x_ {2} = - 8$

Answer 2

Answer:

hello : x=2 and x = -8 is solution

Step-by-step explanation:

x² +6x -16=0

for : x = 2

2² +6(2) -16 = 4+12-16 = 16-16 = 0

for x = - 8

(-8)² +6(-8) -16 = 64 - 48 -16 = 64 -64 = 0