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dimulka [17.4K]
3 years ago
11

1. The organs of sexual reproduction in plants are the

Biology
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

As a plant's reproductive part, a flower contains a stamen (male flower part) or pistil (female flower part), or both, plus accessory parts like sepals, petals, and nectar glands (Figure 19). The stamen is that the male sex organ. It consists of a pollen sac (anther) and a protracted supporting filament.

Explanation:

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What is epidermal tissue​
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Epidermal tissue system is the outermost covering of plants. It consists of epidermis, stomata and epidermal outgrowths. Epidermis is generally composed of single layer of parenchymatous cells compactly arranged without intercellular spaces. But it is interrupted by stomata. In leaves some specialized cells which surround the stomata are called the guard cells.

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3 years ago
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1. In 1889, August Weismann, a German biologist, conducted an experiment attempting to produce mice
-Dominant- [34]

Answer: inheritance of acquired traits

Explanation: I took the test and aced it so I hope this helped!!

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2 years ago
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Where do cells get the chemicals needed to synthesize other molecules?
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Answer:

the chemicals needed to produce molecules comes from the food which an organism eat.

Explanation:

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7 0
3 years ago
A crayfish’s swimmerets are used only for swimming.<br> a. True<br> b. False
marta [7]
Its false because lobsters have swimmerets as well and they dont use them only for swimming
6 0
3 years ago
Indicate the expected number of Barr bodies in interphase cells of individuals with Klinefelter syndrome; Turner syndrome; and k
madreJ [45]

Answer:

Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.

One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.

Then,

The number of Barr bodies with Klinefelter would be:

Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.

Similarly, for

Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)

Now, as per the question, the bar bodies for karyotypes given

47,XYY: (n-1) = (1-1) = 0 Barr bodies

47,XXX: (n-1) = (3-1) = 2 Barr bodies

48,XXXX: (n-1) = (4-1) = 3 Barr bodies

7 0
3 years ago
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