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zimovet [89]
4 years ago
6

I'LL UP-VOTE :P

Mathematics
1 answer:
Kaylis [27]4 years ago
3 0
1/3 x 1/4 = 1/12
because, 1 x 1 =1
                3 x 4 = 12
So the correct answer is c) 1/12
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What is the approximate measure of I
mrs_skeptik [129]
Let θ = m∡I

tan θ = 20/21
tan⁻¹ (20/21) = θ

θ ≈ 43.60° or if you need to round to another decimal point, plug the equation I put in bold into a calculator. 
3 0
3 years ago
Read 2 more answers
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
Help.....................
Olin [163]

Answer:

C

Step-by-step explanation:

6 0
3 years ago
Order theses from least to greatest
agasfer [191]
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3 years ago
46.2 x 10 to the power of -2<br> Can someone show me the work to this problem
irga5000 [103]
The answer is .462 It's just mulitplying
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4 years ago
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