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PSYCHO15rus [73]
3 years ago
13

What would P(A|B) be?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
P(A \cap B) = P(A) \cdot P(B)

so

P(A) = \frac{P(A \cap B)}{P(B)} = \frac{2/3}{3/4} = \frac{8}{9}

also, if A or B happens but not both, you add the chances and subtract the chance that both are happening.

P(A|B) = P(A) + P(B) - P(A \cap B) = \frac{8}{9} +\frac{3}{4} - \frac{2}{3} = \frac{35}{36}

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Answer:

= 186 F

136 F is taken as the steam point

-50 F is taken as the ice point

∴ difference = steam point - ice point

= 136- (-50)

= 186F

3 0
3 years ago
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Simplify by dividing negative three over eight divided by five over nine..
IRISSAK [1]

Answer:

-15/24 or -0.625

Step-by-step explanation:

-3/8 ÷ 5/9

First, we can use the multiplication fraction conversion trick to switch the last fraction's numerator and denominator

It would look like this: -3/8 x 9/5

Use the cross out method to simplify the fractions as lowest as possible

-1/8 x 3/5 = -15/24

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4 years ago
Will mark brainliest if correct. Find what the measurement of angles a-d are and state the reason
Furkat [3]

Answer: D = 70  

              A = 30

Explanation: d is parallel to 70 degrees, 40 is parallel to e, and the whole set of angles is 180 so 180 - 2(70) + 2(40)  = 30 so D = 70 and A = 30

7 0
3 years ago
Help me on this question! Jake can carry 6 1/4 pounds of wood in from the barn.His father can carry 1 5/7 times as much as jake.
ioda

\text{ Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

<em><u>Solution:</u></em>

From given question,

Number of pounds Jake carry = 6\frac{1}{4} \text{ pounds }

Number of pounds his father carry is 1\frac{5}{7} times as much as jake

To find: Number of pounds Jake father can carry

<em><u>Convert the mixed fractions to improper fractions</u></em>

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

\rightarrow 6\frac{1}{4} = \frac{4 \times 6+1}{4} = \frac{25}{4}\\\\\rightarrow 1\frac{5}{7} = \frac{7 \times 1+5}{7} = \frac{12}{7}

<em><u>Then according to question,</u></em>

\text{Pounds father carry } = \frac{12}{7} \text{ times the pounds jake carry }\\\\\text{Pounds father carry } = \frac{12}{7} \times \frac{25}{4}\\\\\text{Pounds father carry } = \frac{75}{7}\\\\\text{In terms of mixed fractions, }\\\\\text{Pounds father carry } = \frac{75}{7} = 10\frac{5}{7}

\text{ Thus, Jake father can carry } 10\frac{5}{7} \text{ or } \frac{75}{7} \text{ pounds }

3 0
3 years ago
Shawndra said that it is not possible to draw a trapezoid that is a rectangle, but it is possible to draw a square that is a rec
ICE Princess25 [194]

Shawndra is correct

 

She made two statements, and both are true:

 

1. It is not possible to draw a trapezoid that is a rectangle.

This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of parallel sides, whereas a rectangle is a parallelogram (i.e. it has two pairs of parallel sides)</span>

 

2. It is possible to draw a square that is a rectangle.

This is true because a rectangle refers to any parallelogram with right angles. A square is also a parallelogram (has two pairs of opposite sides) with right angles. In fact, all squares are rectangles; only that they are a special kind of rectangle, where all the sides are equal in length.

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4 years ago
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