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4 years ago

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There are 12 boys and 14 girls in a class. One of the students is selected at random to represent the class at student council.

What is the probability that the student selected is a girl?

1 answer:

Tema [17]4 years ago

8 0

Answer:

Step-by-step explanation:

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What is the LCM of 168 and 196.

romanna [79]

Answer:

1176

hope this will help you

7 0

3 years ago

Read 2 more answers

1. Construct a table of values of the following functions using the interval of 5

Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

$g(x) = \frac{x^3 + 3x - 5}{x^2}$

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When $x = -5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}$

$g(-5) = \frac{-125 -15 - 5}{25}$

$g(-5) = \frac{-145}{25}$

$g(-5) = -5.8$

When $x = -4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}$

$g(-4) = \frac{-64 -12 - 5}{16}$

$g(-4) = \frac{-81}{16}$

$g(-4) = -5.0625$

When $x = -3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}$

$g(-3) = \frac{-27 -9 - 5}{9}$

$g(-3) = \frac{-41}{9}$

$g(-3) = -4.56$

When $x = -2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}$

$g(-2) = \frac{-8 -6 - 5}{4}$

$g(-2) = \frac{-19}{4}$

$g(-2) = -4.75$

When $x = -1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}$

$g(-1) = \frac{-1 + 3 - 5}{1}$

$g(-1) = \frac{-3}{1}$

$g(-1) = -3$

When $x = 0$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(0) = \frac{0^3 + 3(0) - 5}{0^2}$

$g(0) = \frac{0 + 0 - 5}{0}$

$g(0) = \frac{- 5}{0}$

<em>g(0) = undefined</em>

When $x = 1$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(1) = \frac{1^3 + 3(1) - 5}{1^2}$

$g(1) = \frac{1 + 3 - 5}{1}$

$g(1) = \frac{-1}{1}$

$g(1) = 1$

When $x = 2$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(2) = \frac{2^3 + 3(2) - 5}{2^2}$

$g(2) = \frac{8 + 6 - 5}{4}$

$g(2) = \frac{9}{4}$

$g(2) = 2.25$

When $x = 3$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(3) = \frac{3^3 + 3(3) - 5}{3^2}$

$g(3) = \frac{27 + 9 - 5}{9}$

$g(3) = \frac{31}{9}$

$g(3) = 3.44$

When $x = 4$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(4) = \frac{4^3 + 3(4) - 5}{4^2}$

$g(4) = \frac{64 + 12 - 5}{16}$

$g(4) = \frac{71}{16}$

$g(4) = 4.4375$

When $x = 5$

$g(x) = \frac{x^3 + 3x - 5}{x^2}$ becomes

$g(5) = \frac{5^3 + 3(5) - 5}{5^2}$

$g(5) = \frac{125 + 15 - 5}{25}$

$g(5) = \frac{135}{25}$

$g(5) = 5.4$

<em>Hence, the complete table is:</em>

x ---- g(x)

-5 --- -5.8

-4 --- -5.0625

-3 --- -4.56

-2 --- -4.75

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0

3 years ago

Mary can run 5 kilometers in 18.75 minutes.

trasher [3.6K]

Answer:

30 minutes

Step-by-step explanation:

Find the unit rate (time per SINGLE kilometer).

5/5=1 18.75/5=3.75

Multiply 3.75 (unit rate) by 8.

3.75 x 8=30

8 0

3 years ago

Please i need helpp ion get math at all

fiasKO [112]

Answer:

you have to use the Pythagorean theorem. a^2 + b^2= c^2

72^2 + b^2 = 75^2

5184 + b^2 = 5625 (subtract 5184 from both sides)

b^2= 441 (find the square root of each side)

b= 21

4 0

3 years ago

What's is 8(x-3)+8=5x-22

atroni [7]

8 (x - 3) + 8 = 5x - 22

First, expand. / Your problem should look like: 8x - 24 + 8 = 5x - 22
Second, simplify 8x - 24 + 8 to 8x - 16. / Your problem should look like: 8x - 16 = 5x - 22
Third, subtract 5x from both sides. / Your problem should look like: 8x - 16 - 5x = -22
Fourth, simplify 8x - 16 - 5x to 3x - 16. / Your problem should look like: 3x - 16 = -22
Fifth, add 16 to both sides. / Your problem should look like: 3x = -22 + 16
Sixth, simplify -22 + 16 to -6. / Your problem should look like: 3x = -6
Seventh, divide both sides by 3. / Your problem should look like: x = $- \frac{6}{3}$
Eighth, simplify $\frac{6}{3}$ to 2. / Your problem should look like: x = -2

Answer: x = -2

5 0

4 years ago