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Nata [24]
3 years ago
15

Sean is driving to visit his friend in another state.In the first hour he travels 1/5 of the total distance. In the second hour

he travels 34 miles. If he has 194 more to go, how far apart do the friends live?
Mathematics
1 answer:
lozanna [386]3 years ago
7 0

Answer:

They live 285 miles apart

Step-by-step explanation:

Let the total distance be x miles

Sean is driving to visit his friend in another state. In the first hour he travels 1/5 of the total distance. This means that he drove x/5 in the first hour. In the second hour he travels 34 miles. That means

Total distance driven in the first and second hour is

(x/5 + 34)miles

He still has 194 miles more to go.

Therefore,

The total distance is the sum of the distance travelled in the first and second hour + the remaining distance.

x = x/5 + 34 + 194

x = x/5 + 228

Cross multiplying

5x = x + 1140

4x = 1140

x = 1140/4 = 285 miles

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Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

4 0
3 years ago
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Janine had job offers at two companies. One company offers a starting salary of 28,000 with a raise of 3000 each year. The other
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In 8 years both salaries will be the same

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