Answer:The correct answer is 2/3x + 17
Step-by-step explanation:
Try adding the two and think of it mentally as if you were drinking the amount of cups of water that's what I do when I have questions like these :))
we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
<h3>What is the last digit of the product of all the numbers between 11 and 29?</h3>
Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.
Then we have the product:
P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28
Now, notice that there is a 20 there.
Any number times 20 will end with a zero, then:
P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)
Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
If you want to learn more about products:
brainly.com/question/10873737
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Answer:
D.) because it cannot be expressed as a ratio of integers
Step-by-step explanation:
The root of any integer that is not a perfect square is irrational. 5 is not a perfect square, so is irrational—it cannot be expressed as the ratio of integers.
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<em>Proof</em>
Suppose √5 = p/q, where p and q are mutually prime. Then p² = 5q².
If p is even, then q² must be even. We know that √2 is irrational, so the only way for q² to be even is for q to be even—contradicting our requirement on p and q.
If p is odd, then both p² and q² will be odd. We can say p = 2n+1, and q = 2m+1, so we have ...
p² = 5q²
(2n+1)² = 5(2m+1)²
4n² +4n +1 = 20m² +20m +5
4n² +4n = 4(4m² +4m +1)
n(n+1) = (2m+1)²
The expression on the left will be even for any integer n; the expression on the right will be odd for any integer m. This equation cannot be satisfied for any integers m and n, so contradicting our assumption √5 = p/q.
We have shown using "proof by contradiction" that √5 cannot be the ratio of integers.
Answer:
d
Step-by-step explanation:
13 red, 1 king of spade, 1 ace of club
