Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Max has two more steps left to do. They are described in choice D.
The experimental probability of the arrow stopping on Section 2 will be 
. is the ratio of the favorable event to the total number of events.
<h3>What is probability?</h3>
Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.
No of arrows given in the different section ;
Section 1=18
Section 2=30
Section 3=32
The probability that the arrow stopping on Section 2 is found as;
Hence, the experimental probability of the arrow stopping on Section 2 will be .
More about the probability link is given below.
brainly.com/question/795909
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(n/6 + 8) - 3 = 7
(n/6 + 8) - 3 + 3 = 7 + 3
n/6 + 8 - 8 = 10 - 8
n/6 = 2
(n/6)(6) = 2(6)
n = 12
Answer:
Options (C)
Step-by-step explanation:
For the congruence of the triangles ΔADB and ΔADC,
Statements Reasons
1). AB ≅ AC 1). Given
2). AD ≅ AD 2). Reflexive property
3). ∠BAD ≅ ∠CAD 3). Given
4). ΔABD ≅ ΔCAD 4). SAS postulate
Therefore, Options (C) will be the correct option.
