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inn [45]
3 years ago
7

Hi :) this lesson is about 30-60-90 triangles.

Mathematics
1 answer:
hjlf3 years ago
4 0

Answer:

5 times the square root of 3

Step-by-step explanation:

To get the longest side of a 30-60-90 triangle, you take the shortest side and multiply it by the square root of 3.

5*(square root of 3)

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Is 14/35 and 21/42 proportional
PIT_PIT [208]
1.Simplified each one 
2/5 (both divided by 7) ,  1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10    ,    (1/2)*(5/5)=5/10
Now the dominators are the same ,you can just compare the numerators. It is 4:5
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3 years ago
Work out m and c for the line: 3 y + 2 x = − 1
dem82 [27]

Answer:

Step-by-step explanation:

5 0
2 years ago
Which equation represents the relationship between the x-and y-values shown in the table.
Dmitrij [34]

C. y = 3x - 4

Step-by-step explanation:

Given coordinates:

(2, 2), (3, 5), (5, 11), (7, 17)

The equation of any straight line is

y = mx + c

Where

m = Gradient

c = Constant

Gradient = y2 - y1/x2 - x1

Substitute any two values of y with the respective values of x.

Gradient = 17 - 2/7 - 2

= 15/5

= 3

Substitute the gradient into the general formula.

y = 3x + c

Substitute any value of the coordinate to the equation

2 = 3(2) + c

2 = 6 + c

c = -4

From y = mx + c,

substitute the values of m, the gradient, and c, the constant.

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5 0
2 years ago
Find the values of x and y
Readme [11.4K]

y=5

x=30

Explanation: since all 3 angles of triangles are marked equal we can see that it is equilateral which means 8y=40 so y=5. Then we can find that the other triangle is an 120 30 30 triangle thus x is 30. You can also do this if you can see straight away that the big triangle is a 30-60-90 triangle and just use 90-60.

3 0
3 years ago
COF
Flauer [41]

Answer:

X \sim N(\mu= 70, \sigma=15)

From this info and using the empirical rule we know that we will have about 68% of the scores between:

\mu -\sigma = 70-15=55

\mu +\sigma = 70+15=85

95 % of the scores between:

\mu -2\sigma = 70-2*15=40

\mu +2\sigma = 70+2*15=100

And 99.7% of the values between

\mu -3\sigma = 70-3*15=25

\mu +3\sigma = 70+3*15=115

Step-by-step explanation:

For this problem we can define the random variable of interest as "the student grades" and we know that the distribution for X is given by:

X \sim N(\mu= 70, \sigma=15)

From this info and using the empirical rule we know that we will have about 68% of the scores between:

\mu -\sigma = 70-15=55

\mu +\sigma = 70+15=85

95 % of the scores between:

\mu -2\sigma = 70-2*15=40

\mu +2\sigma = 70+2*15=100

And 99.7% of the values between

\mu -3\sigma = 70-3*15=25

\mu +3\sigma = 70+3*15=115

5 0
3 years ago
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