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Varvara68 [4.7K]
3 years ago
5

Landen spent LL hours at the beach last weekend. Matéo spent 15\%15% fewer hours at the beach than Landen did.

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Answer: B, D, and E

0.85L

or

L-0.15L

or

L(1-0.15)

or

L - \frac{15}{100}L

L - \frac{3}{20}L

Step-by-step explanation:

L is the number of hours Landen spent at the beach. Mateo spent 15% less time. This means he spent 85% of it. So 0.85 times L. We can also calculate it by subtracting the difference between the two kids. - 15%. 15% is 0.15L or \frac{15}{100}L. We subtract by L-0.15L or as L - \frac{15}{100}L. This fraction can simplify to L - \frac{3}{20}L

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It increased by 25%

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no. 4

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-2x+22&lt;18 <br><br>solve the inequality
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-2x+222}

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Solve the equation for y.
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Step-by-step explanation:

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2 years ago
Rewrite the expression below.<br><br> -2a( a + b - 5)+ 3 (-5a + 2b) +b (6a + b - 8)
Paul [167]

Answer:

b^2 + 4 a b - 2 b - 2 a^2 + -5 a

Step-by-step explanation:

Simplify the following:

-2 a (a + b - 5) + 3 (2 b - 5 a) + b (6 a + b - 8)

-2 a (-5 + a + b) = 10 a - 2 a^2 - 2 a b:

10 a - 2 a^2 - 2 a b + 3 (2 b - 5 a) + b (6 a + b - 8)

3 (2 b - 5 a) = 6 b - 15 a:

10 a - 2 a^2 - 2 a b + 6 b - 15 a + b (6 a + b - 8)

b (-8 + 6 a + b) = -8 b + 6 a b + b^2:

10 a - 2 a^2 - 2 a b - 15 a + 6 b + -8 b + 6 a b + b^2

Grouping like terms, 10 a - 2 a^2 - 2 a b - 15 a + 6 b - 8 b + 6 a b + b^2 = b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a):

b^2 + (6 a b - 2 a b) + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

a b 6 + a b (-2) = 4 a b:

b^2 + 4 a b + (6 b - 8 b) - 2 a^2 + (10 a - 15 a)

6 b - 8 b = -2 b:

b^2 + 4 a b + -2 b - 2 a^2 + (10 a - 15 a)

10 a - 15 a = -5 a:

Answer:  b^2 + 4 a b - 2 b - 2 a^2 + -5 a

8 0
3 years ago
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