What is the LCM of these two numbers??? Please helppppppp!!!!

What is the value of the expression below? 3/8+(-4/5)+(-3/8)+5/4

Crazy boy [7]

It will help you!

=-17/40+-3/8+5/4

= -4/5+5/4

= 9/20

And the answer is 9/20 or decimals (0.45)

4 0

3 years ago

Read 2 more answers

The transitive property holds true for similar figures.<br><br> Always<br> Sometimes<br> Never

liubo4ka [24]

Answer: Always.

Step-by-step explanation:

The transitive property holds true for similar figures always because similar figures have similar shapes, the same angles and dimensions are proportional.

For example:- If figure 1 is similar to figure 2 then both have same shape and same angles and dimensions are proportional .

If figure 2 is similar to figure 3 then both have same shape and same angles and dimensions are proportional .

⇒ figure 1 is similar to figure 3 the both have same shape and same angles and dimensions are proportional as the figure 2 .

Thus the transitive property holds true for similar figures always.

5 0

3 years ago

Read 2 more answers

Solve the system of linear equations by graphing

REY [17]

The answer to this problem is (x,y) = (-4,2)

4 0

3 years ago

Read 2 more answers

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

2 years ago

Compute the partial products.add them 349x 59

Semmy [17]

20,591................

8 0

2 years ago