C. y= x + 4
If you plug it in
1 + 4=5
6 + 4 = 10
8 + 4 = 12
and so forth
Answer:
see explanation
Step-by-step explanation:
Since AC = BC then ΔABC is isosceles with base angles
∠BAC =∠ABC, thus
3x + x = 70
4x = 70 ( divide both sides by 4 )
x = 17.5
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∠ADC is an external angle of ΔABD and the external angle is equal to the 2 opposite interior angles, hence
y = 70 + x = 70 + 17.5 = 87.5
Answer:
Step-by-step explanation:
hello :
here is an solution :
<u>√(a^6b³)</u> = <u> a³√b³ </u><u /> = <u>a³√b³</u> = <u>a³√b³</u>
98 √(49 × 2) √49√2 7√2
It is the answer choice c)
