The answer is 79 and 80.
x - the number of the first locker
x + 1 - the number of the consecutive locker
Their sum is 159.
x + x + 1 = 159
2x + 1 = 159
2x = 159 - 1
2x = 158
x = 158 / 2
x = 79
x - the number of the first locker: x = 79
x + 1 - the number of the consecutive locker x + 1 = 79 + 1 = 80
Answer:
39 and 65
Step-by-step explanation:
the ratio of the two numbers is 3 : 5
sum the parts of the ratio, 3 + 5 = 8 parts
divide the sum by 8 to find the value of one part of the ratio
104 ÷ 8 = 13 ← value of 1 part of the ratio , then
3 parts = 3 × 13 = 39
5 parts = 5 × 13 = 65
the two numbers are 39 and 65
<span>if
1c<span>m3</span>=1mm</span>
then<span><span>
1942×1c<span>m3</span>=1942×1mm</span></span>
I cant see the link ummmmmm
