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Vesna [10]
3 years ago
14

Solve 2cos2x + cosx − 1 = 0 for x over the interval [0, 2pi ).

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

2cos^2x+cosx-1 = 0

2cos^2x + 2cosx - cosx - 1 = 0

(2cos^2x + 2cosx) - (cosx + 1) = 0

2cosx(cosx + 1) - 1(cosx + 1) = 0

(cosx + 1)(2cosx - 1) = 0

cosx+1 = 0 or 2cosx-1 = 0

cosx+1 = 0 gives cosx = -1, x = PI

2cosx-1 = 0 gives cosx = 1/2, x = PI/3 or x = 5PI/3

answer: x = PI/3 or x = PI or x = 5PI/3
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Will give 25 points if someone can answer this page
Studentka2010 [4]

Answer:

Domain = {1,2,3,4,5,6} and Range = {42,49,56,63,70,77The given function is :

y = 7x + 35

Where

x is no of members

y is the monthly cost

Your group has enough money for up to six members to joim fitness club. It means domain (the set of input values) are:

Domain = {1,2,3,4,5,6}

Put x = 1 to 6 one by one,

y = 7(1) + 35 = 42

y = 7(2) + 35 = 49

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Range = {42,49,56,63,70,77}

ocabanga44 and 6 more users found this answer helpful

THANKS

4

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