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Vesna [10]
3 years ago
14

Solve 2cos2x + cosx − 1 = 0 for x over the interval [0, 2pi ).

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

2cos^2x+cosx-1 = 0

2cos^2x + 2cosx - cosx - 1 = 0

(2cos^2x + 2cosx) - (cosx + 1) = 0

2cosx(cosx + 1) - 1(cosx + 1) = 0

(cosx + 1)(2cosx - 1) = 0

cosx+1 = 0 or 2cosx-1 = 0

cosx+1 = 0 gives cosx = -1, x = PI

2cosx-1 = 0 gives cosx = 1/2, x = PI/3 or x = 5PI/3

answer: x = PI/3 or x = PI or x = 5PI/3
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Answer:

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Step-by-step explanation:

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5 0
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<em>Solution</em><em>,</em>

<em>P=</em><em>{</em><em>7</em><em>,</em><em>8</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>9</em><em>}</em>

<em>Q=</em><em>{</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>7</em><em>,</em><em>1</em><em>9</em><em>}</em>

<em>P </em><em>U </em><em>Q=</em><em>{</em><em>7</em><em>,</em><em>8</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>9</em><em>}</em><em> </em><em>U </em><em>{</em><em> </em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>7</em><em>,</em><em>1</em><em>9</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em> </em><em>7</em><em>,</em><em>8</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>7</em><em>,</em><em>1</em><em>9</em><em>}</em>

<em>P-Q=</em><em>{</em><em>7</em><em>,</em><em>8</em><em>,</em><em>1</em><em>2</em><em>,</em><em>1</em><em>9</em><em>}</em><em>-</em><em>{</em><em>1</em><em>2</em><em>,</em><em>1</em><em>5</em><em>,</em><em>1</em><em>7</em><em>,</em><em>1</em><em>9</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em>Hope </em><em>it</em><em> helps</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Answer:

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Step-by-step explanation:


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