A) multiple the 3 x 4 and add 1.
3 x 4 = 12 + 1 = 13
13/3
B) (7 x 3) + 2 = 23/3
C) (4 x 2) + 1 = 9/2
D) (2 x 8) + 7 = 23/8
Given that the probability <span>is
modeled by the function
![y=3(257,959)^x[tex] where x is the impurity concentration and y, given as a percent, is the probability of the fuse malfunctioning.\\Then, the probability of the fuse malfunctioning for an impurity concentration of 0.17 is given by [tex]y=3(257,959)^{0.17}=3(8.316941)=24.95](https://tex.z-dn.net/?f=y%3D3%28257%2C959%29%5Ex%5Btex%5D%20%20where%20x%20is%20the%20impurity%20%0Aconcentration%20and%20y%2C%20given%20as%20a%20percent%2C%20is%20the%20probability%20of%20the%20fuse%20%0Amalfunctioning.%5C%5CThen%2C%20the%20%3C%2Fspan%3Eprobability%20of%20the%20fuse%20malfunctioning%20for%20an%20impurity%20concentration%20of%200.17%20is%20given%20by%20%5Btex%5Dy%3D3%28257%2C959%29%5E%7B0.17%7D%3D3%288.316941%29%3D24.95)
Therefore, the <span>probability of the fuse malfunctioning for an impurity concentration of 0.17 is 25% to the nearest percent.</span>
</span>
Step-by-step explanation:
We need to find each of the following as a rational number in the form of p/q
(a) (3/7)² (b) (7/9)³ (c) (-2/3)⁴
Solution,
(a) (3/7)²

(b) (7/9)³

(c) (-2/3)⁴

Hence, this is the required solution.
Answer:
x + 79 = 90
x = 11 degrees
Step-by-step explanation: