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Len [333]
3 years ago
14

Ashley is diving in the ocean. She wants to reach a coral reef that is 60 feet below sea level; that is, the reef’s elevation is

-60 feet. She decides to safely descend to the reef from the ocean’s surface in increments of 10 feet. Answer the following questions to learn more about Ashley’s rate of descent.
Ashley dives in increments of 10 feet. What rational number represents diving 10 feet below sea level?
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

I am not positive that this is correct

Step-by-step explanation:

So if she want to reach a reef that has a elevation of -60 and she descends at a rate of 10 feet my guess the rational number that would represent this problem would be

-60/10

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DaniilM [7]
This isn’t a question this is just a statement
7 0
3 years ago
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A proportional relationship between the number of pounds of cabbage (x) and the price in dollars (y) is graphed, and the ordered
Marta_Voda [28]

Answer: A. 1 pound of cabbage will cost 40 cents.  B. (10,4) means that 10 pounds of cabbage will cost 4 dollars.

Step-by-step explanation:

If it is proportional that means the y value divided by the x value will give you a constant slope.

So using that use the coordinates (5,2)  to find the cost of 1 pound of cabbage.

2/5 = 0.4

so you could write the equation y= 0.4x  where x is the number of pound.

Part A:     y= 0.4(1)    

                y= $0.40  which means one pound of cabbage will cost 40 cents.

Part B.    (10,4) in this case it will means that for 10 pounds of cabbage it will cost $4.

   Plot it into the equation and find out

 in the coordinates (10,4) 4 is the y and 10 is the x

   4= 0.4(10)

  4= 4  

Which means it true that 10 pounds of cabbage will cost 4 dollars.

5 0
3 years ago
Approximate the value of the square root of 110 to the nearest hundredth
DaniilM [7]

Answer:

10.4900

Step-by-step explanation:

pls make a brainliest

3 0
3 years ago
Which expression is it equivalent to?
horrorfan [7]
Option A) Is the answer. \boxed{\mathbf{\dfrac{3f^3}{g^2}}}

For this question; You are needed to expose yourselves to popular usages of radical rules. In this we distribute the squares as one-and-a-half fractions as the squares eliminate the square roots. So, as per the use of fraction conversion from roots. It becomes relatively easy to solve and finish the whole process more quicker than everyone else. More easier to remember.

Starting this with the equation editor interpreter for mathematical expressions, LaTeX. Use of different radical rules will be mentioned in between the steps.

Radical equation provided in this query.

\mathbf{\sqrt{\dfrac{900f^6}{100g^4}}}

Divide the numbered values of 900 and 100 by cancelling the zeroes to get "9" as the final product in the next step.

\mathbf{\sqrt{\dfrac{9f^6}{g^4}}}

Imply and demonstrate the rule of radicals. In this context we will use the radical rule for fractions in which a fraction with a denominator of variable "a" representing a number or a variable, and the denominator of variable "b" representing a number or a variable are square rooted by a value of "n" where it can be a number, variable, etc. Here, the radical of "n" is distributed into the denominator as well as the numerator. Presuming the value of variable "a" and "b" to be greater than or equal to the value of zero. So, by mathematical expression it becomes:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{\dfrac{a}{b}} = \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}, \: \: a \geq 0 \: \: \: b \geq 0}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{\sqrt{g^4}}}

Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{g^4} = g^{\frac{4}{2}}}

\mathbf{\therefore \quad \dfrac{\sqrt{9f^6}}{g^2}}

Exhibit the radical rule for two given variables in this current step to separate the variable values into two new squares of variables "a" and "b" with a radical value of "n". Variables "a" and "b" being greater than or equal to zero.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}, \: \: a \geq 0 \: \: \: b \geq 0}}

So, the square roots are separated into root of 9 and a root of variable of "f" raised to the value of "6".

\mathbf{\therefore \quad \dfrac{\sqrt{9} \sqrt{f^6}}{g^2}}

Just factor out the value of "3" as 3 × 3 and join them to a raised exponent as they are having are similar Base of "3", hence, powered to a value of "2".

\mathbf{\therefore \quad \dfrac{\sqrt{3^2} \sqrt{f^6}}{g^2}}

The radical value of square root is similar to that of the exponent variable term inside the rooted enclosement. That is, similar exponential values. We apply the following radical rule for these cases for a radical value of variable "n" and an exponential value of "n" with a variable that is powered to it.

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^n} = a^{\frac{n}{n}} = a}}

\mathbf{\therefore \quad \dfrac{3 \sqrt{f^6}}{g^2}}

Again, Apply the radical exponential rule. Here, the squar rooted value of radical "n" is enclosing another variable of "a" which is raised to a power of another variable of "m", all of them can represent numbers, variables, etc. They are then converted to a fractional power, that is, they are raised to an exponent as a fractional value with variables constituting "m" and "n", for numerator and denominator places, respectively. So:

\boxed{\mathbf{Radical \: \: Rule: \sqrt[n]{a^m} = a^{\frac{m}{n}}, \: \: a \geq 0}}

\mathbf{Since, \quad \sqrt{f^6} = f^{\frac{6}{2}} = f^3}

\boxed{\mathbf{\underline{\therefore \quad Required \: \: Answer: \dfrac{3f^3}{g^2}}}}

Hope it helps.
8 0
3 years ago
How do you solve this problem.
Nat2105 [25]

Answer:

8 were yoused  because 8 times 3 =24 so if you subtract you get 8

Step-by-step explanation:

8 0
4 years ago
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