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Volgvan
3 years ago
7

Find the possible values of the constant k if the roots of the quadratic equation

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

{b}^{2}  - 4ac = 0 \\  { ( - k  - 2)}^{2}  - 4(1)(4)  = 0\\  {k}^{2}  + 4k + 4 - 4 = 0 \\ {k}^{2}  + 4k = 0 \\ k(k + 4) = 0 \\  \therefore \: k = 0 \:  or \: k =  - 4

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Please Need Help ASAP!!!!
Zepler [3.9K]
No it isn't. 5x is 5*x. not plus. so x would be 19 since 5*19=95
4 0
3 years ago
F(x)=2x+3/4x+5<br>find f(-9)<br>​
mylen [45]

\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

f(x) =  \frac{2x + 3}{4x + 5} \\

For f(-9), put "-9" for every value of "x".

↬f( - 9) =  \frac{2( - 9) + 3}{4( - 9) + 5}\\

↬ f(-9) =  \frac{ - 18 + 3}{ - 36 + 5} \\

↬ f(-9) =  \frac{ - 15}{ - 31}\\

↬ f(-9)=  \frac{15}{31}\\

↬f(-9)=  0.48\\

\bold{ \green{ \star{ \red{Mystique35}}}}⋆

6 0
3 years ago
Read 2 more answers
I don't understand this question. I was hoping someone could help.​
iris [78.8K]

Answer:

A

Step-by-step explanation:

The constant rate of change in this question simply means the slope

To get the slope, we simply get two points and apply the slope equation;

The points are;

(3,60) and (6,30)

The slope equation is;

m = (y2-y1)/(x2-x1) = (30-60)/(6-3) = -30/3 = -10 ft/s

So our answer is the first option as it represents a decent of -10 ft/s

8 0
3 years ago
~[~p\/(r/\~s)] true or false
viktelen [127]

false

20 more characters


7 0
3 years ago
Factor -8x^3-2x^2-12x-3
inysia [295]

-8x^3-2x^2-12x-3\\\\=-2x^2(4x+1)-3(4x+1)\\\\=(4x+1)(-2x^2-3)\\\\=\boxed{-(4x+1)(2x^2+3)}

5 0
4 years ago
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