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3 years ago

7

Find the possible values of the constant k if the roots of the quadratic equation

1 answer:

Anastasy [175]3 years ago

5 0

Answer:

${b}^{2} - 4ac = 0 \\ { ( - k - 2)}^{2} - 4(1)(4) = 0\\ {k}^{2} + 4k + 4 - 4 = 0 \\ {k}^{2} + 4k = 0 \\ k(k + 4) = 0 \\ \therefore \: k = 0 \: or \: k = - 4$

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Hello!!

════ ⋆★⋆ ════

$\mathbb{A~N~S~W~E~R~:}$

$= r$ · $2$

➡ $\Huge \sf \mathbb \color{}\underline{\colorbox{ANSWER~WITH~EXPLANATION ~!}{}}$

$\mathfrak{apply~the~fraction~rule: }$ $a$ $\frac{b}{c} =\frac{a~. ~b }{c}$

$\mathfrak{apply~rule: }$ $a$ · $1 = a$

$r$ · $1$ · $4 = r$ · $4$

$=\frac{r~.~4}{2}$

$\mathfrak{divide~the~numbers~: }$ $\frac{4}{2} = 2$

$= r$ · $2$

So, your answer will be is :

$= r$ · $2$

$\color{}{Hope\:it\:helps. ..}$

#LearnWithBrainly

$\mathbb{A~N~S~W~E~R~:}$

$\mathfrak{Jace}$

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3 years ago