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Lerok [7]
4 years ago
15

A package of 8 batteries costs $4.72.What is the cost per battery?

Mathematics
1 answer:
Marat540 [252]4 years ago
7 0
SOLUTION:

8 batteries = $4.72

8 ÷ 8 = 4.72 ÷ 8

1 battery = $0.59

Therefore, the cost of per battery is $0.59.

Hope this helps! :)
Have a lovely day! <3
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PLEASE HELP ME WITH THIS LAST QUESTION
NemiM [27]

Answer:

1) 28

2) 22

3) 6

4) Skewed right

5) 17

Step-by-step explanation:

have a nice day :3

8 0
3 years ago
Find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)
Murljashka [212]

Answer:

Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

Step-by-step explanation:

We need to find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

Endpoints of a diameter A(−6, 3) and B(4, 7)

The general equation of circle is: (x-h)^2+(y-k)^2=r^2

Where r is radius and (h,k) is centre of circle.

Finding centre of circle

The midpoint of diameter is centre of circle.

So, finding midpoint of A(−6, 3) and B(4, 7)

The formula used is: Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

We have x_1=-6, y_1=3, x_2=4, y_2=7

Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\Midpoint=(\frac{-6+4}{2} ,\frac{3+7}{2} )\\Midpoint=(\frac{-2}{2} ,\frac{10}{2} )\\Midpoint=(-1 ,5)

So, we get Midpoint (x,y)=(-1,5)

Finding radius of circle

Radius of circle can be found by first finding diameter using distance formula and then divide it by 2.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\Distance=\sqrt{(4-(-6))^2+(7-3)^2} \\Distance=\sqrt{(4+6)^2+(7-3)^2} \\Distance=\sqrt{(10)^2+(4)^2} \\Distance=\sqrt{100+16}\\Distance=\sqrt{116}\\Distance = 10.77

So, Diameter = 10.77

Radius = Diameter/2 = 5.38

Equation of circle

Equation of circle having centre(-1,5) and radius r = 5.38 is:

(x-h)^2+(y-k)^2=r^2\\(x-(-1))^2+(y-5)^2=(5.38)^2\\(x+1)^2+(y-5)^2=28.94

So, Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

4 0
3 years ago
Classify the following triangle. check all that apply​
Karo-lina-s [1.5K]

Answer:

Options (A), (B)

Step-by-step explanation:

Option A.

Two sides of the given triangle are equal. Therefore, the given triangle is an isosceles triangle.

Option (B).

Given triangle has a right angle. Therefore, it's a right triangle.

Option (C).

Only two sides of the given triangle are equal. Therefore, it's not an equilateral triangle.

Option (D).

Although this triangle has two acute angles (less than 90°) but the third angle is 90°. Therefore, this triangle is not an acute triangle. It's a right triangle.

Option (E).

A scalene triangle is a triangle having all sides different in measure but the given triangle is an isosceles triangle. Therefore, it's not a scalene.

Option (F).

Any angle of this triangle is not more than 90°. Therefore, the given triangle is not an obtuse triangle.

5 0
3 years ago
True or false euclidean geometry is geometry on a sphere
DerKrebs [107]
Fathe answer is false
4 0
3 years ago
In ΔLMN, \overline{LN} LN is extended through point N to point O, m∠NLM = (x+1)^{\circ}(x+1) ∘ , m∠LMN = (x+15)^{\circ}(x+15) ∘
mixer [17]

Answer:

26 degree

Step-by-step explanation:

We are given that  in triangle

\angle NLM=(x+1)^{\circ}

\angke LMN=(x+15)^{\circ}

\angle MNO=(4x+6)^{\circ}

\angle MNO+\angle MNL=180^{\circ}

By using linear pair angles property

\angle MNL=180-\angle MNO=180-(4x+6)

\angle MNL+\angle NLM+\angle LMN=180^{\circ}

By using triangle angles sum property

180-(4x+6)+x+15+x+1=180

2x+16=180-180+4x+6

16-6=4x-2x=2x

2x=10

x=\frac{10}{2}=5

Substitute the value

\angle MNO=4(5)+6=20+6=26^{\circ}

3 0
3 years ago
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