Answer:
25.9%
Step-by-step explanation:
Note: you did not provide any attached image detailing the dimension of the cylinder however, let us arrange some dimension for explanation purpose
let the dimension of the cylinder be
radius= 3in
height= 5 in
Step two
The expression for the total surface area of a cylinder is
T. S. A. =2πrh+2πr2
substitute
T. S. A. =2*3.142*3*5+2*3.142*3^2
T. S. A. =94.26+56.556
T. S. A. =150.816 in^2
Now let us find the error
%error= actual -expected/expected*100
%error= 190 -150.816/150.816*100
%error= 39.184/150.816*100
%error= 0.259*100
%error= 25.9%
Now, you can use the dimension you have for the cylinder to calculate the total surface area, from there, you can solve for the error by following the steps above
Answer:
$63.08
Step-by-step explanation:
43.5 * 1.45 = 63.08
A)3/10
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Answer:
x=-2.5 if the function is
Step-by-step explanation:
has discontinuities when the denominator is 0.
You will either have a hole or a vertical asymptote depending on what happens to the numerator after you find when the bottom is 0.
That is whatever you found that makes the bottom 0, if it makes the top also 0 then you will have a hole at x=the number that made the bottom 0.
If it makes the top anything other than 0, then it is a vertical asymptote at x=the number you found that made the bottom 0.
Let's do this now.
When is -4x-10 equal to 0?
We have to solve the equation:
-4x-10=0
Add 10 on both sides:
-4x=10
Divide both sides by -4:
x=10/-4
Reduce by dividing top and bottom by 2:
x=5/-2
x=-5/2
or
x=-2.5 (if you want decimal form)
Now does it make the top 0? This is the deciding factor on whether you have a hole at x=-2.5 or a vertical asymptote at x=-2.5.
Let's see.
8(-2.5)-3=-23
Since the top is not 0 at x=-2.5 then you have a vertical asymptote at x=-2.5.
If the top were 0, then you would have had a hole at x=-2.5.
Answer:
The percentage of the students scored higher than 89% is 15.87%
Step-by-step explanation:
we are given
The average test scores for a particular test in algebra was 84
so, mean is 84

a standard deviation of 5
so,

we have
x=89
now, we can use z-score formula

now, we can plug values


now, we can use calculator
and we get

So,
The percentage of the students scored higher than 89% is 15.87%