Figure not drawn to scale.
1 answer:
Though you do not provide a diagram, I am going to give this a try by assuming that O is the center of the circle, OA is a radius, and angle AOB is a central angle that measures 88 degrees.
We want to find out the area of sector AOB. First, we need to find the area of the entire circle. The area of a circle is given by
and since the radius of this circle is equal to 1, the area is 
Next we need to know what fraction of the circle sector AOB represents. The distance around the circle is 360 degrees but the central angle that intercepts arc AB is 88 degrees. That meas that the fraction of the circle the sector represents is given by
We multiply this by the area to obtain
which is the area of the sector.
We want to find out the area of sector AOB. First, we need to find the area of the entire circle. The area of a circle is given by
Next we need to know what fraction of the circle sector AOB represents. The distance around the circle is 360 degrees but the central angle that intercepts arc AB is 88 degrees. That meas that the fraction of the circle the sector represents is given by
We multiply this by the area to obtain
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Answer:
Answers are below
Step-by-step explanation:
The domain of the function is all real numbers.
The range of the function is also all real numbers.
I graphed the function on the graph below.
Answer:
7
Step-by-step explanation:
The function can be written in vertex form as ...
f(x) = -(x +1)^2 +7
The vertex is then identifiable as (-1, 7). The y-coordinate is 7.
_____
Vertex form is ...
f(x) = a(x -h)^2 +k
where "a" is the vertical scale factor, and (h, k) is the vertex point. It is convenient to arrive at this form by factoring "a" from the first two terms, then adding and subtracting the square of the remaining x-coefficient inside and outside parentheses.
f(x) = -(x^2 +2x) +6
f(x) = -(x^2 +2x +1) + 6 -(-1) . . . . completing the square
f(x) = -(x +1)^2 +7 . . . . . . . . . . . . vertex form; a=-1, (h, k) = (-1, 7)
