Ask question

Ask question

All categories

3 years ago

5

Which liquid would be the most difficult to raise or lower the temperature of?

1 answer:

Afina-wow [57]3 years ago

4 0

Any liquid that contains a high heat capacity

You might be interested in

Use the drop-down menus to complete the statement.

lbvjy [14]

Answer:

kinetic and electrical

Explanation:

answered on edu

6 0

3 years ago

Read 2 more answers

Which option below correctly compares the average annual dose of background radiation to the dose liked to an increased cancer r

julia-pushkina [17]

The answer for this question would be choice "<span>B. The average annual dose of background radiation is 250 times smaller than the dose linked to increased cancer risk."

You only have to compare 4.0 x 10^-4 and 1.0 x 10^-1. And if you can observe carefully, when you try to multiply the average annual dose of background radiation by 250, you would get 0.1 which is equivalent to the amount of annual dose linked to increased cancer risk. Therefore, the answer is B.</span>

6 0

3 years ago

What is needed for a complete circuit? a Charge flows along a complete conducting path b High Resistance c Wires connected to a

Ilia_Sergeevich [38]

Answer:

a Charge flows along a complete conducting path

Explanation:

6 0

3 years ago

State some important uses of magnet

GarryVolchara [31]

Use of magnet:

Magnets are used in magnetic compass, doorbells, refrigerators.
Magnets are used in dynamos, motors, loudspeakers, microphones etc.
Ceramic magnets are used in computers.
Magnets are used in toys to give a magic effect.

3 0

3 years ago

Read 2 more answers

Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th

Anna71 [15]

The correct answer to the question is : $100\ ^0C$

EXPLANATION :

As per the question, the specific heat of gold is given as c = $0.130\ J/g^0C$

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

$dT=\ \frac{dQ}{mc}$

$=\ \frac{195}{15\times 0.130}$

$=\ 100\ ^0C$ [ANS]

Hence, the change in temperature is 100 degree celsius.

5 0

4 years ago