Answer:
0.045 m/s²
Explanation:
Let the mass of Earth be 'M' and radius be 'R'.
Given:
Mass of the new planet (m) = one-sixth of Earth's mass =
Radius of new planet (r) = 6 times Earth's radius =
We know that, acceleration due to gravity of a planet of mass 'M' and radius 'R' is given as:
Now, this is acceleration due to gravity on Earth.
Now, acceleration due to gravity of new planet is given as:

Now, the value of 'g' on Earth is approximately 9.8 m/s². So,

Therefore, the free fall acceleration on the surface of this planet is 0.045 m/s².