**Answer:**

**0.045 m/s²**

**Explanation:**

**Let the mass of Earth be 'M' and radius be 'R'.
**

Given:

Mass of the new planet (m) = one-sixth of Earth's mass =

Radius of new planet (r) = 6 times Earth's radius =

We know that, acceleration due to gravity of a planet of mass 'M' and radius 'R' is given as:

Now, **this is acceleration due to gravity on Earth.**

Now, **acceleration due to gravity of new planet** is given as:

Now,** the value of 'g' on Earth is approximately 9.8 m/s²**. So,

Therefore, **the free fall acceleration on the surface of this planet is 0.045 m/s².**