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3 years ago

Please help 33-40, thanks!

Mathematics

1 answer:

kogti [31]3 years ago

6 0

33. -8 belongs to:

Set of real numbers; all rational and irrational numbers
Set of integers; positive and negative whole numbers

34. 14 belongs to:

Set of natural numbers; all positive whole numbers
Set of real numbers; all rational and irrational numbers

35. 9.23 belongs to:

Set of real numbers; all rational and irrational numbers

36. $1\frac{5}{9}$ belongs to:

Set of real numbers; all rational and irrational numbers

37. Zero (0) belongs to:

Set of Integers; all positive and negative whole numbers
Set of real numbers; all rational and irrational numbers

38. -1 belongs to:

Set of integers; all positive and negative whole numbers
Set of real numbers; all rational and irrational numbers

39. 1/2 belongs to:

Set of real numbers; all rational and irrational numbers

40. 0.3 where 3 is recurring belongs to:

Set of real numbers; all rational and irrational numbers

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An operator at the top of a lighthouse sights a sailboat. The point from which the sighting is made is 25 m above sea level. The

Aneli [31]

Answer:

141.78 m

Step-by-step explanation:

Let d = distance of boat from the base of the lighthouse

Tan 10 = 25/d

d tan 10 = 25

d = 25/tan 10

d = 141.78 m

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2 years ago

Aha please help!!!!! im a bit confused lol

Stels [109]

Answer:

e : g = 2 : 7

Step-by-step explanation:

e/f = 3/7

e = 3f/7

f/g = 2/3

g = 3f/2

e/g = (3f/7)/(3f/2) = 2/7

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2 years ago

*Select all that apply.*

Korvikt [17]

I'm for sure know that it is function is linear but i would wait for others to answer also

5 0

3 years ago

Read 2 more answers

You have $36,948.61 in a brokerage account, and you plan to deposit an additional $3,000 at the end of every future year until y

Luba_88 [7]

Current amount in account
P=36948.61

Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n

Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11

We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000

We can solve this by trial and error.

The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.

So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.

So it takes 15.00 years to reach the goal of 280000 years.

8 0

3 years ago

Question 3 of 10

katovenus [111]

Answer:

No solution

Step-by-step explanation:

Not sure tbh

8 0

3 years ago