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navik [9.2K]
3 years ago
11

How do you solve for this????​

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

D: 29,000

Step-by-step explanation:

Add all the numbers up then divide them by the amount of numbers there are.

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I have 3 equations 9x+6, 2(5x-3) and 5y+14 how do i solve for x?
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Set the equation equal to zero.

9x+6=0
Subtract 6 from both sides
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Divide both sides by 9
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or -2/3

2(5x-3)=0
Distribute
10x-6=0
add 6 to both sides
10x=6
Divide by 10 on both sides
x=6/10 or 4/5

5y+14=0
-14 from both sides
5y=-14
divide both sides by 5
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8 0
3 years ago
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cluponka [151]

3 ^x = -3

then, x would be -1

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How does a set of integers differs from the set of whole numbers ? Please help
MariettaO [177]
The difference between set of whole numbers and a set of integers is that:

Whole numbers = {0, 1, 2, 3, 4, 5...}
Integers = {..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5...}

If we name contents of the first set as n, in the second set you can have 2n-1 numbers (because we count 0 only once in both sets).
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Which of the fractional factors will result in a product that increases when multiplied by the fraction in the image?
Delicious77 [7]

the fraction in the image is 2 1/2

let's try each choice

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3) 3/3 x 2 1/2 = 2 1/2

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who is giving you these questions?

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