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harkovskaia [24]
2 years ago
15

The sale price of every item in a store is 85% of its usual price. Find the price of the following items given their usual price

. The usual price of a soccer ball is $19.80, what
is its sale price?
Mathematics
1 answer:
White raven [17]2 years ago
7 0

Answer:

$16.83

Step-by-step explanation:

If the usual price is $19.80 and they are on sale for 85% of the usual price, you can set this up in the form of a proportion.

\frac{85}{100} = \frac{x}{19.80}

With this, you first multiply 85*19.80 and then you divide that answer by 100 to solve for x, the sale price.

Another way you can approach it is by changing 85% into it's decimal form (.85) and multiplying this by the original price (19.80).

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Figure 1 is dilated to get Figure 2.
Ierofanga [76]
To find this:
10*____=24
The blank is 2.4, which is the scale factor

7 0
4 years ago
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Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam
notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

\sigma_p = \sqrt{\frac{p(1-p)}{n} }

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3\sigma_p

and U.C.L = p + 3\sigma_p

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

\sigma_p = \sqrt{\frac{p(1-p)}{n} }

On substituting p = 0.054 and  n = 100, we get

\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }

    = 0.0226

c) The control limits for the control chart are:

Upper control limit =  p + 3\sigma_p

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3\sigma_p

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

#SPJ4

7 0
1 year ago
5^7 + 5^6 = _* 6<br><br> AWARDING BRAINLIEST
enyata [817]

Answer:

1.91666666666666666666...

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The length of a rectangle is 5 less than twice the width. If the perimeter of the rectangle is 146 centimeters, find the dimensi
artcher [175]
Length of rectangle = 5 less than 2x width
Perimeter = 146 cm

<u>Equations we will use...</u>
w = width
(2w - 5) = length (l)
perimeter (p) = 2(l + w)

<u>Substitute equation for </u><u>length</u><u> into equation for </u><u>perimeter</u>
p = 2(l + w)
146 = 2((2w - 5) + w)     
[use distributive prop.]
146 = 4w - 10 + 2w        [combine like terms]
146 = 6w -10                  
[solve for w]
156 = 6w
w = 26 cm

<u>Now substitute width back into the </u><u>equation</u><u> for length...</u>
l = 2w - 5
l = 2(26) - 5
l = 47

Double check to make sure values added up to 146 cm
w + w + l + l = 146
26 + 26 + 47 + 47 = 146
146 = 146

Therefore, the width is 26 cm and the length is 47 cm.


8 0
4 years ago
Please someone help me with this
Ivenika [448]

Answer:

See explanation

Step-by-step explanation:

Triangle ABC ahs vertices at points A(-4,-4), B(-1,-2) and C(-1,-4).

<u>1 way:</u> First reflect this triangle across the y-axis to form the triangle A''B''C'' which vertices are at points A''(4,-4), B''(1,-2) and C''(1,-4).

Then translate this triangle 7 units up to form the triangle A'B'C' with vertices:

A'(4,-4+7)=A'(4,3)\\ \\B'(1,-2+7)=B'(1,5)\\ \\C'(1,-4+7)=C'(1,3)

<u>2 way:</u> First translate this triangle 7 units up to form the triangle A''B''C'' which vertices are at points A''(-4,3), B''(-1,5) and C''(-1,3).

Then reflect this triangle across the y-axis to form the triangle A'B'C' with vertices:

A'(-(-4),3)=A'(4,3)\\ \\B'(-(-1),5)=B'(1,5)\\ \\C'(-(-1),3)=C'(1,3)

8 0
3 years ago
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