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noname [10]
3 years ago
10

Factor completely: 16x2 − 81

Mathematics
1 answer:
patriot [66]3 years ago
8 0
16 times 2 is 32. 81-32 is....49. Did I answer your question?
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Give answer fast...<br>it's very important for me....<br>then I give you 20 thanks...(◍•ᴗ•◍)❤​
Vedmedyk [2.9K]

Answer:

I have the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Choose the equation below that represents the line passing through the point -3,-1 with the slope of four
tresset_1 [31]

Answer:

y+1 = 4(x+3)

Step-by-step explanation:

To write the equation of a line use the point slope form by substituting m = 4 and the point (-3,-1).

y - y_1 =m(x-x_1)\\y --1 = 4(x--3)\\y+1 = 4(x+3)

5 0
3 years ago
PLS HELP ASAP calculate the distance between the two points. (18, -24) &amp; (87, 100)
GarryVolchara [31]

Answer:

<h3>The answer is 141.90 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(18, -24) & (87, 100)

The distance between them is

d =  \sqrt{ ({18 - 87})^{2} +  ({ - 24 - 100})^{2}  }  \\  =  \sqrt{ ( { - 69})^{2}  + ( { - 124})^{2} }  \\  =  \sqrt{4761 + 15376}  \\  = \sqrt{20137}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  = 141.90489773...

We have the final answer as

<h3>141.90 units</h3>

Hope this helps you

5 0
3 years ago
Drake's yard measures 24 feet by 30 feet. His garden, which is part of the yard, measures 3 feet by 9 feet. What is the area of
tia_tia [17]
720 squared ft

I hope this helps:)
7 0
4 years ago
Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A
liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality \sin ^2\theta +\cos ^2\theta \geq 1

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

\sin \theta = side opposite to \theta/hypotenuse

\cos  \theta = side adjacent to \theta/hypotenuse

\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta

\cos  \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta

So, coordinates of A = \left ( \cos \theta ,\sin \theta  \right )

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by x^2+y^2=1

Put (x,y)=\left ( \cos \theta ,\sin \theta  \right )

\cos ^2\theta +\sin ^2\theta =1

So, (x,y)=\left ( \cos \theta ,\sin \theta  \right ) satisfies the equation x^2+y^2=1

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) inside the circle, \cos ^2\theta +\sin ^2\theta

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) outside the circle, \cos ^2\theta +\sin ^2\theta >1

So, only points on the circle satisfy the given inequality.

4 0
3 years ago
Read 2 more answers
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