Question

The length of a rectangle is twice its width. If the perimeter ot the rectangle is 42 ft, find its area.​

Answer 1

Answer:

x length

y width

2x=y

2x+2y=42/2

x+y=21 x+y=21

x+2x=21

3x=21/÷3

x=7

7+y=21

y=21-7=14

7×14=98 the area of a rectangle

Answer 2

Answer:  98 ft²

Step-by-step explanation:

Length (L) = 2w

width (w) = w

Perimeter (P) = 2L + 2w

                 42 = 2(2w) + 2w

                 42 = 4w + 2w

                  42 = 6w

                    7 = w

L = 2w

  = 2(7)

  = 14

Area = L · w

         = 14 · 7

         = 98