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AleksAgata [21]
3 years ago
10

Answer and will mark brainliest

Mathematics
1 answer:
White raven [17]3 years ago
6 0

Answer:

C

Step-by-step explanation: i did it

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I’m doing my finals I need to finsih pls help
Citrus2011 [14]
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8 0
3 years ago
Are the given lengths 24, 60, 66, sides of a right triangle?
GarryVolchara [31]


24+60=84>66

60+66=126>24

66+24=90>60


Therefore, the lengths are the sides of a triangle because the sum of lengths of two sides must be greater than the third side. All the sum of length of 2 sides are greater than the third side.

5 0
3 years ago
Read 2 more answers
Find the area of triangle ABC. Give your answer correct to 1 decimal place AC=7 Cb=12 a=72 degrees b=59 degrees
Tems11 [23]

Answer:

31.7 cm²

Step-by-step explanation:

The area (A) of the triangle is calculated as

A = \frac{1}{2} absinC

where a, b are the 2 sides given and C the angle between them

∠ C = 180° - (72 + 59)° = 180° - 131° = 49° , thus

A = 0.5 × 12 × 7 × sin49° ≈ 31.7 cm² ( to 1 dec. place )

3 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
4 years ago
Determine whether the relation {(6, –3),<br> (4, 1), (7, –2), (–3, 1)} is a function. Explain.
soldi70 [24.7K]

Answer:

A ifs it's not right sorry

5 0
1 year ago
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