Answer:
(x+20) + (x-9)
Step-by-step explanation:
The answer is: " 1024π units² " ; or; " 3215.36 units² " .
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A = π * r² ;
A = π * 32² = 1024 π units² ;
or, using "3.14" for "π" ;
1024 * π = 1024 * (3.14) = 3215.36 units² .
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Answer:
area of the circle is 254.47yd^2
Answer and Step-by-step explanation:
For these system of equations, it would be easier to use the substitution method, as we are have one equation that is being equaled to a variable.
Plug the second equation into the value of b for the first equation.
5a + 3(-2a + 3) = 11
Distribute the 3.
5a - 6a + 3 = 11
Simplify.
-a + 3 = 11
Subtract 3 from both sides of the equation.
-a = 8
Divide both sides by -1.
a = -8
Now, we can plug this value into the second equation.
-2(-8) + 3 = b
Multiply -2 and -8 together.
16 + 3 = b
Add together 16 and 3.
19 = b
<u>a = -8</u>
<u>b = 19</u>
<u></u>
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
Hello from MrBillDoesMath!
Answer:
Choice C, sqrt(3-x)
Discussion:
Have no fear, MBill is here!
The quotient is
sqrt (9-x^2) / sqrt( 3+x) = => as sqrt(a)/sqrt(b) = sqrt(a/b), b <> 0
sqrt ( (9-x^2)/( 3+x) ) = => as 9 - x^2 = (3-x) * (3+x)
sqrt ( (3-x)(3+x) /(3+x) ) = => cancel (3+x) from num. and denom.
sqrt( 3-x)
This is Choice C
Note the domain restriction -3 < x < = 3 guarantees that division by zero can't happen.
Thank you,
MrB
