Question

On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 3), point B is at (negative 5, negative 1), and point C is at (3, negative 1). What is true about △ABC? Select three options AB ⊥ AC The triangle is a right triangle. The triangle is an isosceles triangle. The triangle is an equilateral triangle. BC ∥ AC

Answer 1

Answer:

Option C, The triangle is an isosceles triangle.

Step-by-step explanation:

On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 3), point B is at (negative 5, negative 1), and point C is at (3, negative 1).

$\left(-1,3\right), \left(-5,-1\right),\left(3,-1\right)$

Use distance formula to find $AB^2 , BC^2, CA^2\\AB^2 = (-1+5)^2+(3+1)^2 =32\\AC^2= ((-1-3)^2+(3+1)^2 = 32\\BC^2 = (-5-3)^2+(-1+1)^2 = 64$

We find only two sides are equal and third side is not equal

Hence this is an isosceles triangle

Answer 2

Answer:

Options A, B, and C

Step-by-step explanation:

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