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Bumek [7]
3 years ago
15

Here is a picture of a math problem.

Mathematics
1 answer:
Dvinal [7]3 years ago
5 0
Is true the answer is 60%
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HELP PLEASE!!!
ch4aika [34]

Answer:

The population of Bear in 2050 is 4750000

Step-by-step explanation:

A) The exponential growth equation for bear is as follows -

dN/dT = rmax * N

Where dN/dT = change in population

rmax is the maximum rate of change

N = Base population

B) Here the per capita rate of increase (r) will always be a positive value irrespective of the and hence we will assume this population to be growing exponentially.

C) dN/dT = rmax * N

D) dN / 5 = 2.5 * 380,000

dN = 5*2.5 * 380000

= 4750000

8 0
3 years ago
The local fish market sells both salmon and tuna for $5.35 per pound. If you buy 3.4 pounds of tuna and 2.7 pounds of salmon, wh
boyakko [2]
3.4 + 2.7 = 6.1
6.1(5.35) = 32.635
So, you would be charged $32.64 or letter C :)
3 0
3 years ago
Determine whether the point (4,2) is in the solution set of the system of inequalities below. 4x + y < 2 y > –2
sladkih [1.3K]

Answer:

False

Step-by-step explanation:

4x + y < 2

y > –2

Substitute the point into the inequalities and see if they are true

4(4) + 2 < 2

16+2 < 2

18 <2  False

2 > –2  True

Since one is false the point is not a solution

8 0
3 years ago
Find the volume<br> If the rectangular prism of this 3m,11m,3m and what is the answer
sveta [45]

Answer:

99 m³

Step-by-step explanation:

The volume (V) of a rectangular prism is calculated using the formula

V = lbh

where l is the length, b the breadth and h the height, hence

V = 3 × 11 × 3 = 99 m³

4 0
4 years ago
What is the simplified form of this expression 7(^3sqrt2x)-3(^3sqrt16x)-3(^3sqrt8x)
trasher [3.6K]

Answer:

<h2>7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x</h2>

Solution,

7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\  = 7 \sqrt[3]{2x}  - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x}  - 3 \times  \sqrt[3]{2 \times 2 \times 2x}  \\  = 7 \sqrt[3]{2x}  - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 3 \times 2 \times  \sqrt[3]{2x}  - 3 \times 2x \\  = 7 \sqrt[3]{2x}  - 6 \sqrt[3]{2x}  - 6x

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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