Answer:
See below
Step-by-step explanation:
a. How fast does the plane fly during the first leg of the trip?
b. How fast does the plane fly during the last leg of the trip?
c. What system of equations might be helpful in this scenario?
<u>s - speed of the plane, w - speed of the wind, equations:</u>
d. Solve this system of equations using the best method.
Add the equation together to get:
- 2s = 1100 ⇒ s = 550 mph
- w = 550 - 430 = 120 mph
e. How fast is the wind?
f. How fast does the plane fly without any wind?
Answer:
x=-27
Step-by-step explanation:
27+4x=3x
So 27=-x
x=-27
Answer:
<h2>38</h2><h2 />
Step-by-step explanation:
see attached
The required equation of a line is y = -3x- 1
<h3>Equation of a line</h3>
The equation of a line in slope-intercept form is expressed as:
y = mx + b
where
m is the slope
b is the y-intercept
Using the coordinate point (0, -1) and (-1, 2)
Slope = 2-(-1)/-1-0
Slope = 3/-1
Slope =-3
Since the line crosses the y-axis at (0, -1), hence the value of b is -1
Determine the equation
y = mx + b
y = -3x + (-1)
y = -3x- 1
Hence the required equation of a line is y = -3x- 1
Learn more on equation of a line here; brainly.com/question/18831322
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