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monitta
2 years ago
7

Im stuck on this to could you guys explain how you do this

Mathematics
1 answer:
OverLord2011 [107]2 years ago
8 0

The required equation of a line is y = -3x- 1

<h3>Equation of a line</h3>

The equation of a line in slope-intercept form is expressed as:

y = mx + b

where

m is the slope

b is the y-intercept

Using the coordinate point (0, -1) and (-1, 2)

Slope = 2-(-1)/-1-0

Slope = 3/-1

Slope =-3

Since the line crosses the y-axis at (0, -1), hence the value of b is -1

Determine the equation

y = mx + b

y = -3x + (-1)

y = -3x- 1

Hence the required equation of a line is y = -3x- 1

Learn more on equation of a line here; brainly.com/question/18831322

#SPJ1

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there ya go bud hope this helps

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3 years ago
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8 0
2 years ago
Read 3 more answers
How do i solve y+4=4/3(x+1)
ICE Princess25 [194]
Y + 4 = 4/3(x + 1)...first we distribute
y + 4 = 4/3x + 4/3 ...now we subtract 4 from both sides
y = 4/3x + 4/3 - 4
y = 4/3x + 4/3 - 12/3
y = 4/3x - 8/3 <======
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in standard form, it is :
y = 4/3x - 8/3
-4/3x + y = -8/3
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Step-by-step explanation:

4 0
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