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3 years ago

Can someone please help me.. answer choices below A.46 B.134 C.136 D.146

Mathematics

2 answers:

Over [174]3 years ago

5 0

The answer is a C. Or D.

Vesnalui [34]3 years ago

3 0

C b/c 180° - 44° = 136°. Angles DEB & AED add up to 180° b/c they are supplementary angles.

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On the last school spirit day, 5 out of every 7 students wore school colors. Based on this information, if 560 students attend t

arlik [135]

Answer:400

Step-by-step explanation:

Multiply the total number of students by the ratio given

5/7(560)

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3 years ago

The bill at a restaurant is $28.48, not including tax. A family wants to leave an 18% tip. How much money

Nezavi [6.7K]

Answer:

5.13

Step-by-step explanation:

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3 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

Definition

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

Definition II

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

Examples

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

Absolute Value Property I

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

Conclusion

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers

Please help quicky!!!!!!!!!!

olga55 [171]

Answer:

≈ 2,826 cm^3

Step-by-step explanation:

V = πr^2h

V = 3.14 · 10^2 · 9

V = 3.14 · 100 · 9

V = 314 · 9

V = 2,826

6 0

3 years ago

Given: m =-2/3

Elenna [48]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is (( D )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6 0

3 years ago