Answer:
482 km
63.94 degrees
Step-by-step explanation:
to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.
Cosine rule states that
C = 
where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060
solving now, we have
C = 
C = ![\sqrt{250000 + 90000 - [215000 cos(60) }]](https://tex.z-dn.net/?f=%5Csqrt%7B250000%20%2B%2090000%20-%20%5B215000%20%20%20cos%2860%29%20%20%7D%5D)
C = ![\sqrt{340000 - [215000 * 0.5 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B215000%20%2A%200.5%20%20%7D%5D)
C = ![\sqrt{340000 - [107500 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B107500%20%20%7D%5D)
C =
C = 482 km
The bearing can be gotten by using the Sine Rule.
= 
sina/500 = sin60/482
482 sina = 500 sin60
sina = 
sina = 0.8983
a = sin^-1(0.8983)
a = 63.94 degrees
Answer:
5 2/3
Step-by-step explanation:
2 * 2 5/6
2 * (12+5/6)
2 * (17/6)
34/6
17/3 = 5 2/3
Answer:
i)The correct option is D.) 99.74%
ii) The correct option is B.) 68.26%
Step-by-step explanation:
i) P(10≤X≤70) = P( (10−40)/10 ≤Z≤ (70−40
)/10 ) = Pr(−3≤Z≤3)
= 0.9987 - 0.0013 = 0.99734
Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%
ii)P(2.1≤X≤3.1) = P( (2.1 − 2.6) /0.5 ≤ Z ≤ (3.1−2.6
)/0.5) = Pr(−1 ≤Z ≤1)
)
= 0.8413 − 0.1587 = 0.6826
Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%