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faust18 [17]
3 years ago
12

How do you divide/multiply/add fractions?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0
When you multiply you just multiply the numerators and the denominators.

when you divide, you flip the second fraction over and then multiply the fraction.

when you add fractions you multiply across then add the two fractions.
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What does x equal?<br> 5x + 4 = 1
adoni [48]

Answer:

x= -5

Step-by-step explanation:

8 0
3 years ago
Pls answer 26 and show work
Phoenix [80]

The transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves  translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down

<h3>How to compare the function to its parent function?</h3>

The equation of the transformed function is given as:

y = -(x - 2)^2 - 3

While the equation of the parent function is given as

y = x^2

Start by translating the parent function to the right by 2 units.

This is represented as:

(x, y) = (x - 2, y)

So, we have:

y = (x - 2)^2

Next, reflect the above function across the y-axis

This is represented as:

(x, y) = (-x, y)

So, we have:

y = -(x - 2)^2

Lastly, translate the above function 3 units down

This is represented as:

(x, y) = (x, y - 3)

So, we have:

y = -(x - 2)^2 - 3

Hence, the transformed equation y = -(x - 2)^2 - 3 compared to the parent function involves  translating the parent function to the right by 2 units, reflecting the function across the y-axis and translating the function 3 units down

Read more about function transformation at:

brainly.com/question/8241886

#SPJ1

7 0
2 years ago
Y = -4.5x + 15<br><br> is this not a function, linear function, or nonlinear function
crimeas [40]
This is a linear function
5 0
3 years ago
I need help very bad please. You guys can do any questions just tell me the number
Andrews [41]
Question 10: P=28cm

if l=8 and w=6

Then (8+6)=14
2(14) so 14x2 = 28
So therefore P=28cm
6 0
4 years ago
For what value(s) of k will the relation not be a function?
kolbaska11 [484]

Answer:

  • See below

Step-by-step explanation:

The relation is not a function when x -value is same but y- values are different.

#1

  • k^2 = 4k
  • k = 0, k = 4

#2

  • k^2 - 5k = k + 7
  • k^2 - 6k = 7
  • k^2 - 6k + 9 = 16
  • k - 3 = 4 ⇒ k = 7
  • k - 3 = -4 ⇒ k = -1

#3

  • k^3 - 5k^2 + 3k = -k
  • k^3 - 5k^2 + 4k = 0
  • k(k^2 - 5k + 4) = 0
  • k = 0, k = 1, k = 4

#4

  • |k + 1| + 2 = 8
  • |k + 1| = 6
  • k = 5, k = -7
8 0
3 years ago
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