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ser-zykov [4K]
3 years ago
9

Write a variable expression to describe the rule for the sequence. Then find the 100th term in the sequence. –4, 1, 6, 11, 16, .

. .
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

a+(n-1)d

Step-by-step explanation:

491

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Help fast dont answer if you dont know it
sasho [114]
Well on the second picture your answer is A

2. is B
6 0
3 years ago
A bicycle tire has a radius of 13.25 inches. How far will the bicycle travel in 40 rotations of the tire?
jeka57 [31]

Answer:

the crazy part is that 69 points with the bike

Step-by-step explanation:

5 0
3 years ago
What happens to the center of a figure when it is dilated about the origin?
alina1380 [7]
There are 2 answers for this in my opinion
1. nothing happens because its still in the origin and that won't change
2. depending on which way you turn it the points will change based on that

so if you know how to use a graph you should be good
7 0
4 years ago
Evaluate the following expression for x = 4. <br><br><br> 1+3(x-1)-2x
xz_007 [3.2K]

Answer:

2

Step-by-step explanation:

1+3(x-1)-2x

Substitute the value of x into the equation:

1 + 3(4-1) -2 (4)

1 + 3(3)- 8

1 + 9 - 8

2

8 0
3 years ago
In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. Three of the 8 are in one family
lianna [129]
There are 14 chairs and  8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆  x 3! 

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

4 0
3 years ago
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