There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Answer:
c is the right answer for the problem
Answer:
f(4)=-2
Step-by-step explanation:
f(4)=-4+2=-2
It would be 66.3 because 2% Coverts to .02 then you multiply that to 65 and get 1.3 and then you add that to 65
