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kodGreya [7K]
3 years ago
11

Please help!!!! 25 points!!!

Mathematics
2 answers:
neonofarm [45]3 years ago
6 0
C. the opposite of a negative number is always a positive number
S_A_V [24]3 years ago
4 0
Its C because when they ask you what the opposite of a negative it will be the positive number. EX:  the Opposite of -5 will be 5
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How many blocks with dimensions of One-third times 1 times 1 can fit in a unit cube?
gtnhenbr [62]

Answer: 3

Step-by-step explanation:

Given

The dimension of the small block is

\dfrac{1}{3}\times 1\times 1

The Volume of the cube having unit length is

V=1\times 1\times 1\\V=1\ unit^3

The number of blocks that can be in the unit cube is the division of the volume of the unit cube and block.

\Rightarrow \dfrac{1\times 1\times 1}{\dfrac{1}{3}\times 1\times 1}\\\\\Rightarrow \dfrac{3}{1}=3

7 0
3 years ago
Read 2 more answers
Students in an art class make square tiles that are 5 inches long.They plan to make a row of tiles that is 4 feet 2 inches long.
Nataliya [291]

4 feet is 48 inches.

So 4'2" would be 50 inches.

50/5=10

The class needs to make 10 tiles.

4 0
3 years ago
Find the area of the circle<br> Pls help quick
tigry1 [53]

Answer:

153.86.

Step-by-step explanation:

Formula for area of a circle: A= Pi R (R is radius) squared. First fill in the numbers: 3.14x7^2 Then Solve for the squared: 7^2=49, then finally multiply 49x3.14 which gets you to 153.86.

7 0
3 years ago
Select the two values of x that are roots of this equation x^2-5x+2=0
Nataly [62]

The roots of the equation is x = 4.56 OR x = 0.44

<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}

x =\frac{5 \pm \sqrt{25-8} }{2}

x =\frac{5 \pm \sqrt{17} }{2}

x =\frac{5 + \sqrt{17} }{2} OR x =\frac{5 - \sqrt{17} }{2}

x =\frac{5 + 4.12}{2} OR x =\frac{5 - 4.12}{2}

x =\frac{9.12}{2} OR x =\frac{0.88}{2}

x = 4.56 OR x = 0.44

Hence, the roots of the equation is x = 4.56 OR x = 0.44

Learn more on Quadratic equation here: brainly.com/question/8649555

#SPJ1

3 0
2 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
4 years ago
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