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jeka57 [31]
3 years ago
10

Students in an art class make square tiles that are 5 inches long.They plan to make a row of tiles that is 4 feet 2 inches long.

How many tiles will the students need to make
Mathematics
1 answer:
Nataliya [291]3 years ago
4 0

4 feet is 48 inches.

So 4'2" would be 50 inches.

50/5=10

The class needs to make 10 tiles.

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Factor of 27x ( exponent of 3) - 125
Wewaii [24]

\text{Use}\ a^3-b^3=(a-b)(a^2+ab+b^2)\\\\27x^3-125=3^3x^3-5^3=(3x)^3-5^3=(3x-5)[(3x)^2+(3x)(5)+5^2]\\\\=\boxed{(3x-5)(9x^2+15x+25)}

8 0
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A triangle has side lengths of 77 centimeters, 55 centimeters, and cc centimeters. enter a value to complete the inequality that
PtichkaEL [24]
The correct question is
A triangle has side lengths of 7 centimeters, 5 centimeters, and c centimeters. enter a value to complete the inequality that describes the possible values for c, the length of the third side of the triangle.

we know that
The sum of the lengths<span> of any two </span>sides<span> of a </span>triangle<span> must be greater than the </span>third side

If c is the smallest number, then

5 + c > 7
c > 2

If c is the largest number, then

5+7 > c
12 > c----------> c < 12

the answer is
The value of c must be  in the interval (2,12)


3 0
3 years ago
Jason has a piece of wire that is 62.4 inches long.He cuts the wire into 3 equal pieces.Estimate the length of 1 piece of wire.
vampirchik [111]
20.8 but estimation would be 21.0
7 0
3 years ago
What is the measure of angle Z in the parallelogram shown?
Anarel [89]

Answer:

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Step-by-step explanation:

8 0
3 years ago
I NEED HELP ON THIS PROBLEM!!! PLEASE
Allushta [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

5x+8y=-9\implies 8y=-5x-9\implies y=\cfrac{-5x-9}{8} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{8}} x-9\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

well then, so since this equation has that slope therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{-5}{8}} ~\hfill \stackrel{reciprocal}{\cfrac{8}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{8}{-5}\implies \cfrac{8}{5}}}

so we're really looking for the equation of a line whose slope is 8/5 and runs through (10,10)

(\stackrel{x_1}{10}~,~\stackrel{y_1}{10}) ~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{8}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{\cfrac{8}{5}}(x-\stackrel{x_1}{10})

5 0
2 years ago
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