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patriot [66]
2 years ago
15

Select the two values of x that are roots of this equation x^2-5x+2=0

Mathematics
1 answer:
Nataly [62]2 years ago
3 0

The roots of the equation is x = 4.56 OR x = 0.44

<h3>Quadratic equation</h3>

From the question, we are to determine the roots of the given equation

The given equation is

x² -5x +2 = 0

Using the formula method,

x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}

In the given equation,

a = 1, b = -5, c = 2

Putting the values into the formula,

x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}

x =\frac{5 \pm \sqrt{25-8} }{2}

x =\frac{5 \pm \sqrt{17} }{2}

x =\frac{5 + \sqrt{17} }{2} OR x =\frac{5 - \sqrt{17} }{2}

x =\frac{5 + 4.12}{2} OR x =\frac{5 - 4.12}{2}

x =\frac{9.12}{2} OR x =\frac{0.88}{2}

x = 4.56 OR x = 0.44

Hence, the roots of the equation is x = 4.56 OR x = 0.44

Learn more on Quadratic equation here: brainly.com/question/8649555

#SPJ1

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Need help figuring this equation 1/12c =.6
soldi70 [24.7K]
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To remove a fraction you simply multiply it by its inverse fraction (take the original fraction and flip it! So, multiply it by 12/1 (which is the same as saying 12).

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The 12 cancels out leaving this: 

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If you don't have or are allowed to use a calculator. To compute that you simply make 0.6 into a fraction then multiply the numerator by 12. .6 is in the tenths place so you can write it like this: 
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