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Gwar [14]
2 years ago
10

Please help hard math

Mathematics
1 answer:
Mamont248 [21]2 years ago
4 0
I’m guessing either A or D. I’m it good at math either but I think I personally would go with A.
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Help me please with the steps on how you can find the number of solutions or zeros with these questions!
arsen [322]

Answer:

2x²+5x-9=0

using quadratic formula

a=2 b=5 c=-9

x=[-5±√5²-4(2)(-9)]/2(2)

x=[-5±√97]/4

the zeros are( -5±√97)/4

6 0
2 years ago
Turn 1 1/5 to improper fraction
Alex17521 [72]

Answer:

<h2><em><u>6/5</u></em></h2><h2></h2>

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>
4 0
3 years ago
A 20° sector in a circle has an area of 21.51 pi yd?.
kodGreya [7K]

Answer

____________________________________________________________

This would be 21.5π * 360 / 20 yd^2  =  1215.18 yd^2 ( using pi = 3.14)

____________________________________________________________

5 0
3 years ago
Shane's soccer team played three games in a tournament. Identify the sample
Aleksandr-060686 [28]

Answer:

B

Step-by-step explanation:

the all posible situations are listed in the sample space

www =won all 3 games

wwl= won first 2 games and lost the last and so on...

7 0
3 years ago
Plz help! It’s not hard I just don’t properly understand
jonny [76]

Answer:

a_{13}=2(13)+13=39

39 is the 13th term

Step-by-step explanation:

Okay so essentially the a_n is just a substitute for x.

See how in the equation they put n into the x spot:

y=mx+b\\a_n=mn+b\\a_n=2n+13

They changed the variable names:

y=a_n\\m=2\\n=x\\b=13

Now we know what the n actually means, plus when they ask about the terms youre trying to find it's based off of that n:

When they say, 13 term, they mean a_{13} which would be the 13th answer in the series.  So the first term would be based off of a_1

a_1=2(1)+13\\a_1=15

So whatever number is in the n position by a is what you'll be plugging into the x spot.

y=mx+b\\a_n=2n+13\\a_1=2(1)+13=15\\a_2=2(2)+13=17\\a_3=2(3)+13=19\\a_4=2(4)+13=21\\a_5=2(5) +13=23\\a_6=2(6)+13=25\\a_7=2(7)+13=27\\a_8=2(8) +13=29\\a_9=2(9)+13=31\\a_{10}=2(10)+13=33\\a_{11}=2(11)+13=35\\a_{12}=2(12)+13=37\\a_{13}=2(13)+13=39

These are all the answers leading up to the 13th term they asked for, and you can continue thus same equation with whatever number you can put into the n space.

7 0
2 years ago
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