Answer:
a) ![x=(w+z)\sqrt{w}](https://tex.z-dn.net/?f=x%3D%28w%2Bz%29%5Csqrt%7Bw%7D)
b) ![x=(w+z)\sqrt{z}](https://tex.z-dn.net/?f=x%3D%28w%2Bz%29%5Csqrt%7Bz%7D)
c) ![x=y\sqrt{w}](https://tex.z-dn.net/?f=x%3Dy%5Csqrt%7Bw%7D)
d) ![x=z\sqrt{w}](https://tex.z-dn.net/?f=x%3Dz%5Csqrt%7Bw%7D)
Step-by-step explanation:
The question does not give contain options, but let me provide a list of solutions to the question.
a) x equals the square root of quantity w times the sum of w plus z end quantity
The square root of quantity w is given as
, the sum of w plus z is given as
. Therefore x equals the square root of quantity w times the sum of w plus z end quantity is given as:
![x=(w+z)\sqrt{w}](https://tex.z-dn.net/?f=x%3D%28w%2Bz%29%5Csqrt%7Bw%7D)
b) x equals the square root of quantity z times the sum of w plus z end quantity
The square root of quantity z is given as
, the sum of w plus z is given as
. Therefore x equals the square root of quantity z times the sum of w plus z end quantity is given as:
![x=(w+z)\sqrt{z}](https://tex.z-dn.net/?f=x%3D%28w%2Bz%29%5Csqrt%7Bz%7D)
c) x equals the square root of quantity w times y end quantity
The square root of quantity w is given as
, Therefore x equals the square root of quantity w times y end quantity is given as:
![x=y\sqrt{w}](https://tex.z-dn.net/?f=x%3Dy%5Csqrt%7Bw%7D)
d) x equals the square root of quantity w times z end quantity
The square root of quantity w is given as
, Therefore x equals the square root of quantity w times z end quantity is given as:
![x=z\sqrt{w}](https://tex.z-dn.net/?f=x%3Dz%5Csqrt%7Bw%7D)
Answer:
B
Step-by-step explanation:
Brainliest?
Answer: Im so sorry but I have not done this in such a long time
Step-by-step explanation: Have a good day
Yes it is true that a small deviation means the data set tended to cluster around the mean .
No no no no no no no no no