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3 years ago

Rectangle ABCD is similar to rectangle EFGH. Side CD is proportional to side ___.

Mathematics

2 answers:

a_sh-v [17]3 years ago

4 0

Answer: C. GH

Step-by-step explanation:

Given: Rectangle ABCD is similar to rectangle EFGH.

Side AB is corresponding to EF [First two letters]

Side BC is corresponding to FG [Middle two letters]

Side CD is corresponding to GH [Last two letters]

Side AD is corresponding to EH [First and last letter]

We know that the corresponding sides of the similar figures are proportional.

Therefore, we can see that Side CD is proportional to side GH.

Musya8 [376]3 years ago

3 0

If the rectangle ABCD is similar to rectangle EFGH, side CD is proportional to the side

C. GH

The order of the letters in naming the rectangle gives us which sides are adjacent in rectangle and which sides correspond to the other rectangle.

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If the sum of the measures of the interior angles of a convex polygon is 2160°, how many sides does the polygon have?

olya-2409 [2.1K]

Remember your formula is 180(n-2) where n=number of sides. So start out by dividing by 180, then add 2 to get the sides.

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3 years ago

A piece of wire of length 5050 is cut, and the resulting two pieces are formed to make a circle and a square. Where should the

algol [13]

Answer:

x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

Step-by-step explanation:

Let x be the length of wire that is cut to form a circle within the 5050 wire, so 5050 - x would be the length to form a square.

A circle with perimeter of x would have a radius of x/(2π), and its area would be

$A_c = \pir^2 = \pi (\frac{x}{2pi})^2 = \frac{x^2}{4\pi}$

A square with perimeter of 5050 - x would have side length of (5050 - x)/4, and its area would be

$A_s = (\frac{5050 - x}{4})^2 = \frac{(5050 - x)^2}{16}$

The total combined area of the square and circles is

$\sum A = A_c + A_s = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$

To find the maximum and minimum of this, we just take the 1st derivative, and set it to 0

$A' = \frac{2x}{4\pi} + \frac{-2(5050-x)}{16} = 0$

$\frac{x}{2\pi} - \frac{5050 - x}{8} = 0$

Multiple both sides by 8π and we have

$4x - 5050\pi + x\pi = 0$

$x(4 + \pi) = 5050\pi$

$x = \frac{5050\pi}{4 + \pi} = 2221.5$

At x = 2221.5:

$A = \frac{x^2}{4\pi} + \frac{(5050 - x)^2}{16}$ = 392720 + 500026 = 892746 [/tex]

At x = 0, $A = 5050^2/16 = 1593906$

At x = 5050, $A = \frac{5050^2}{4\pi} = 2029424$

As 892746 < 1593906 < 2029424, x should be cut at 2221.5 to minimize the total combined area, and at 5050 to maximize it.

3 0

3 years ago

20 points!!!

Serjik [45]

Area is found by multiplying the length by the width.

Length = AB = 12

Height = 9

Area = 12 *9 = 108 units^2

The answer is D.

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Answer:

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