What’s one plus one equals to waht
Answer:
x=-5/2
Step-by-step explanation:
4 x^2 +20 x +25 = 0
x^2+5x=-25/4
(b/2)^2=(5/2)^2
x^2+5x+25/4=0
(x+5/2)^2=0
x=-5/2
(Hope this helps)
Answer:
![x\geq 5](https://tex.z-dn.net/?f=x%5Cgeq%205)
Step-by-step explanation:
The function that we have to study in this problem is
![y=\sqrt{x-5}-1](https://tex.z-dn.net/?f=y%3D%5Csqrt%7Bx-5%7D-1)
The domain of a function is defined as the set of all the possible values of x that the function can take.
For a square-root function, there are some limitations to the possible value of the argument in the root.
In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.
Therefore, in this case, we have to set the following condition for the domain:
![x-5\geq 0](https://tex.z-dn.net/?f=x-5%5Cgeq%200)
And by solving, we get
![x\geq 5](https://tex.z-dn.net/?f=x%5Cgeq%205)
which means that the domain of this function is all real numbers equal or greater than 5.
Answer:
lower price = 3
higher price =11
Step-by-step explanation:
p(x) = -2(x-3) (x-11)
Setting equal to zero
0 = -2(x-3) (x-11)
Using the zero product property
x-3 = 0 x-11 =0
x=3 x = 11