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Murljashka [212]

3 years ago

15

Question with last attempt is displayed for your review only

1 answer:

Alika [10]3 years ago

3 0

Answer:

$43.13 = 5.25h + 9$

Step-by-step explanation:

Let's solve this by making an equation.

$9 for the helmet, and $5.25 per hour.

h will stand for hours, C will stand for Amanda's cost.

$C = 5.25h + 9$

Now, substitute in what we learned from the problem.

$43.13 = 5.25h + 9$

This is an equation you can use to solve for the hours.

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What is the distance between points (12, 4) and (12, –10) on the coordinate plane?

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Softa [21]

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3 years ago

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In ΔLMN, \overline{LN} LN is extended through point N to point O, m∠NLM = (x+1)^{\circ}(x+1) ∘ , m∠LMN = (x+15)^{\circ}(x+15) ∘

mixer [17]

Answer:

26 degree

Step-by-step explanation:

We are given that in triangle

$\angle NLM=(x+1)^{\circ}$

$\angke LMN=(x+15)^{\circ}$

$\angle MNO=(4x+6)^{\circ}$

$\angle MNO+\angle MNL=180^{\circ}$

By using linear pair angles property

$\angle MNL=180-\angle MNO=180-(4x+6)$

$\angle MNL+\angle NLM+\angle LMN=180^{\circ}$

By using triangle angles sum property

$180-(4x+6)+x+15+x+1=180$

$2x+16=180-180+4x+6$

$16-6=4x-2x=2x$

$2x=10$

$x=\frac{10}{2}=5$

Substitute the value

$\angle MNO=4(5)+6=20+6=26^{\circ}$

3 0

3 years ago

Please help me solve this!!

Mice21 [21]

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

$Distance =4\ miles$

$Time = 30\ minutes$

Abelito

$Distance = 10\ miles$

$Time = 48\ minutes$

Required:

Who had a greater average speed

Average speed (S) is calculated as:

$S = \frac{Distance}{Time}$

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

$S_B = \frac{4\ miles}{30\ minutes}$

Convert minute to hour

$S_B = \frac{4\ miles}{0.5\ hr}$

$S_B = 8mph$

For Abelito

$S_A = \frac{10\ miles}{48\ minutes}$

Convert minute to hour

$S_A = \frac{10\ miles}{0.8\ hr}$

$S_A = 12.5mph$

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed

5 0

3 years ago